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strojnjashka [21]
3 years ago
7

I need help finding the missing angles

Mathematics
2 answers:
PtichkaEL [24]3 years ago
4 0

Answer:

3) 61

4)60

Step-by-step explanation:

Degger [83]3 years ago
4 0
Explanation is that a triangle total degrees is 180 so you would take the two numbers you have and add them (80 + 39= 119) Then you subtract that number from the total degree from a triangle. (180-119 = 61) Then you get your answer :)
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What is the area of triangle ABC if a = 7, c = 11, and B = 100°?
Dahasolnce [82]

Answer:

7/11

Step-by-step explanation:

5 0
2 years ago
PLS HELP <br> If r = 3s + 1 and t = s - 4, what is r in terms of t?
kirill [66]
R = 3(t+4) + 1
Hope it helps
7 0
3 years ago
Find the midpoint of NP⎯⎯⎯⎯⎯ given N(2a, 2b) and P(2a, 0).
geniusboy [140]

Answer:

(2a, b )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ \frac{1}{2}(x₁ + x₂ ), \frac{1}{2}(y₁ + y₂ ) ]

Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus

midpoint = [ \frac{1}{2}(2a + 2a), \frac{1}{2}(2b + 0 ) ] = (2a, b )

4 0
3 years ago
The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0
3 years ago
4x + 6y - z=-18<br> 3x +2y - 4z = -24<br> - 5x + 3y + 2z = 15<br> find x y and z
Anna71 [15]

Answer:

x = -2, y = -1, z = 4

Step-by-step explanation:

4x + 6y - z=-18

z  = 18  + 4 x  +  6 y

3x +2y - 4z = -24

z  = 6  + (3x)/ 4  +  y /2

- 5x + 3y + 2z = 15

z = 15/2 + (5x)/2 - (3y)/2

18  + 4 x  +  6 y = 6  + (3x)/ 4  +  y /2  = 15/2 + (5x)/2 - (3y)/2

x = -22y/13 - 48/13

4(-22y/13 - 48/13) + 6y - (15/2 + (5(-22y/13 - 48/13))/2 - (3y)/2) = -18

Compute the output value of the variables x and y with respect to the input values of x, y, and z coefficients.

4 0
3 years ago
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