Answer:
The distance between C and P is equal to the distance between C’ and P
Step-by-step explanation:
From the description, the diagram is similar to the one in the attachment.
To answer this question, we that the corresponding vertices of a polygon after a reflection are all equidistant from the line of reflection.
From the diagram, the red dotted line joining C and C', meet on the line of reflectionat P.
This implies that |CP|=|C'P'|.
Therefore the correct answer is :
The distance between C and P is equal to the distance between C’ and P
Answer:
The values of the angles are;
m∠DEA = 62°, m∠ADB = 45°
Step-by-step explanation:
Specify an arc or an angle three letters
Angle opposite an arc on the circumference
m DA ≅ m CB = 62° (Arc between parallel lines are congruent)
∠CAB = 1/2 × m CB = 1/2 × 62° = 31° (Angle at the center = 2 × Angle st the circumference)
∠DBA = 31° (Angle at the center m DA = 2 × Angle st the circumference)
m∠DAB = 104° (Given)
∠ADB = 180° - m∠DAB - ∠DBA = 180° - 104° - 31° = 45° (Interior angles of triangle ΔADB
m∠ADB = 45°
∠AEB = 180 - ∠CAB - ∠DBA = 180° - 31° - 31° = 118°
∠AEB ≅ ∠COD (Vertically opposite angles)
∠DEA ≅ ∠CEB (Vertically opposite angles)
∠AEB + ∠COD + ∠DEA + ∠CEB = 360° (Sum of angles at a point)
118° + 118° + ∠DEA + ∠CEB = 360°
∠DEA + ∠CEB = 360° - 118° - 118° = 124°
Given that ∠DEA = ∠CEB we have;
2 × ∠DEA = 124°
∠DEA = 124°/2 = 62°
m∠DEA = 62°.
Equation represents the difference in the number of foreign and domestic stamps Malik collected: X-34=y
equation represents the total number of stamps Malik collected:
212 = X-34-y
so,
245= X-Y
Situation :
Y= X-34
X-Y= 245
Answer:
See below in bold.
Step-by-step explanation:
a. The factor of growth = 1.08 per year so
P = 20(1.08)^t where P = the bear population and t = the time in years since 2010.
b. It is 10 years after 2010 so:
In 2020: P = 20 * (1.08)^10
= 43 bears.
c. When P = 100 we have:
100 = 20 * (1.08)^t
(1.08)^t = 100/20 = 5
t ln 1.08 = ln 5
t = 20.9 years.
So there will be more than 100 bears in the year 2010 + 21
= 2031.
The hypotenuse is always the biggest side of a right traingle.
