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Triss [41]
3 years ago
12

In Figure 5.26 to the right, ABCDis asquare. Find the measure of<ABD​

Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer:

∠ABD = 45°

Step-by-step explanation:

Since ABCD is a square, its diagonals (Line BD) bisect the angles of the corners of the square (∠ABC) into two equal angles (∠ABD and ∠CBD). The angle of each corner is 90° so you can find ∠ABD.

2(∠ABD) = 90°

∠ABD = 90° ÷ 2

∠ABD = 45°

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A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.
KIM [24]

9514 1404 393

Answer:

  • absolute error: 0.4 kg
  • relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

  7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

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The relative error is the ratio of the absolute error to the actual weight:

  (0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0
3 years ago
10tu^3 + 4v - 3v<br><br> must combine like terms solve or rewrite expression
pshichka [43]

10tu³ + v is the simplified form.

<h3>What is algebraic expression?</h3>

A number, a variable, or a mix of numbers, variables, and operation symbols make up an expression. Two expressions joined by an equal sign form an equation. Word illustration: The product of 8 and 3. Word illustration: The product of 8 and 3 is 11

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5 0
2 years ago
The difference of 16 and a number, divided by 2
valentinak56 [21]

Answer:

8

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Simplify
Scorpion4ik [409]

Answer:

1

Step-by-step explanation:

using the rule of exponents

(\frac{a}{b}) ^{-1} = \frac{b}{a} , then

\frac{123}{321} × \frac{456}{654} × \frac{789}{987} × \frac{321}{123} × \frac{654}{456} × \frac{987}{789}

[ \frac{123}{321} × \frac{321}{123} = 1 , \frac{456}{654} × \frac{654}{456} = 1 , \frac{789}{987} × \frac{987}{789} = 1 ]

= 1 × 1 × 1

= 1

7 0
2 years ago
AnyonE wanna help?????
olga_2 [115]

Answer:

Step-by-step explanation:

a). Let the missing term = a

   (a + 7) + (2x - 6) = -4x + 1

   (a + 2x) + (7 - 6) = -4x + 1

   (a + 2x) + 1 = -4x + 1

   (a + 2x) = -4x

   a = -4x - 2x

   a = -6x

   So the equation is,

  (-6x + 7) + (2x - 6) = -4x + 1

b). (a² + p + 1) - (q + 5a + r) = 4a² -2a + 7

   I have assumed p, q and r are the variables at the blank spaces.

   (a² - q) + (p - 5a) + (1 - r) = 4a² - 2a + 7

   By comparing both the sides of the equation,

    a²- q = 4a²

    q = a² - 4a²

    q = -3a²

    p - 5a = -2a

    p = -2a + 5a

    p = 3a

    1 - r = 7

    r = 1 - 7

    r = -6

    So the equation will be,

    (a² + 3a + 1) - (-3a² + 5a - 6) = 4a²- 2a + 7

3 0
2 years ago
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