Answer:
-\left(\dfrac{1}{2}y+\dfrac{1}{4}\right)=-\dfrac{1}{2}y-\dfrac{1}{4}=-\dfrac{1\cdot2}{2\cdot2}y-\dfrac{1}{4}=\dfrac{-2y}{4}-\dfrac{1}{4}=\dfrac{-2y-1}{4}\\\\=-\dfrac{2y+1}{4}
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Step-by-step explanation:
2(3x + 5) = 5x + 14
6x + 5 = 5x + 14
x = 14-5
x=9
To find h(6), we must plug in 6 into the function.
h(x) = x^2 - 2x - 5
h(6) = 6^2 - 2(6) - 5
= 36 - 12 - 5
= 36 - 17 = 19
Answer: no he was not correct. the answer is 23.
explanation: when you insert 3 into the problem hince, 2(3)^2 + 5. you will get 2x9+5. 18+5=23
Answer:
a to the power of 5
Step-by-step explanation: