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2 years ago

6

A couple had a meal at a restaurant and their bill was $35.50. The sales tax was 7%. They left a 20% tip on the pretax (the pric

e before tax is added) for their server.

1 answer:

krok68 [10]2 years ago

8 0

Answer:

$45.085

Step-by-step explanation:

35.50+27% = $35.50+$9.585

= $45.085

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A gallon of water is equal to 231 cubic inches. How many gallons of water are needed to fill a fish tank that measures 11" high,

9966 [12]

We know that

[volume of a fish tank]=11*14*9-------> 1386 in³

if 1 gallon--------------> 231 in³
X------------------------> 1386 in³
X=1386/231-------> X=6 gallon

the answer is
<span>are needed 6 gallons of water to fill a fish tank</span>

3 0

3 years ago

Solve for v simplify your answer as much as possible: -2 + 3v = -23

seropon [69]

Answer:

-7

Step-by-step explanation:

-2 + 3v = -23 >> -2 + 23 = -3v >> 21 = -3v >> v = -7

3 0

2 years ago

Read 2 more answers

The area of a plot of land is 2496 square meters. A small part of the land is fenced. The ratio of the area of the plot of land

AfilCa [17]

My late response (haha): First, you would write a proportion.

Step 1: 2496 over 48 = x over 31
(x represents the area of the land that is not fenced).

Step 2: Cross multiply
2496 times 31 and x times 48

Step 3: Calculate
77376 = 48x

Step 4: Divide both sides by 48
77376/48 = 1612
48x/48 = x

Step 5: Write it as a sentence
The area of the land that is not fenced is 1612 squared meters.

Hope that helped! Good luck! :]

4 0

3 years ago

I need the product of a^4xa^6

emmainna [20.7K]

A^4 * a^6

exponent rule : x^y * x^z = x^(y + z)

so, a^4 * a^6 = a^(4 + 6) = a^10

3 0

2 years ago

An isosceles triangle has a perimeter of 18 cm. Find a function that models its area A in terms of the length of its base b.

IgorLugansk [536]

So.... notice the picture below

now, we know what the "height" or "altitude" is
now, we also know the perimeter is 18cm

so, k + k + b = 18
or 2k + b = 18
thus $\bf k=\cfrac{18-b}{2}$

so... one can say that $\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad 
\begin{cases}
b=b
\\\\
h=\sqrt{k^2-\left( \frac{b}{2} \right)^2}
\\\\
h=\sqrt{k^2-\frac{b^2}{4}}\\
--------------\\
k=\frac{18-b}{2}\qquad thus\\
--------------\\
h=\sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}
\end{cases}\\\\
-----------------------------\\\\
A=\cfrac{1}{2}\cdot b\cdot \sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}$

and you can simplify it if you wish.. not sure you have to

7 0

2 years ago