Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
The prime factorization of 640 can be written as 27 × 51 where 2, 5 are prime.
Answer:
x2−3x+2=x2−2x−x+2
x(x−2)−1(x−2)=(x−2)(x−1)
Now
x2−4x+3=x2−3x−x+3
x(x−3)−1(x−3)=(x−3)(x−1)
Thus, the only common factor is (x-1)
Option A
hiiiii
To work it out:
(20200 + 14500 + 18800 + 9300 + 2200) divide by the number of regions, in this case 5.
The answer is 13000 which is A
Basically the mean is adding all the numbers divided by the amount of numbers you added. So in this case adding the data of the 5 regions divided by 5.
Hope to have helped :)
3/10 is the smallest hoped this helps
