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Paha777 [63]
2 years ago
14

Find each square root after supplying:

Mathematics
1 answer:
ddd [48]2 years ago
6 0

Answer:

1) 5
2) 0.8
3)  -1.3

4) -\frac{4}{9}

5) ±10

6) ±\frac{7}{12}

Step-by-step explanation:

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2 years ago
Find the value of 26/45 times 5/53 times 28/13 please show fingures and work
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\bf \cfrac{\stackrel{2}{~~\begin{matrix} 26 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{9}{~~\begin{matrix} 45 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{53}\cdot \cfrac{28}{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{2\cdot 28}{9\cdot 53}\implies \cfrac{56}{477}

3 0
3 years ago
In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?
Marina86 [1]

we have

6 = x^{2}- 10x

Complete the square. Remember to balance the equation by adding the same constants to each side

x^{2}- 10x+25=6+25

x^{2}- 10x+25=31

Rewrite as perfect squares

(x-5)^{2}=31

(x-5)=(+/-)\sqrt{31}\\ x1=5+\sqrt{31} \\ x2=5-\sqrt{31}

therefore

the answer is

the solutions are

x1=5+\sqrt{31} \\ x2=5-\sqrt{31}

7 0
2 years ago
Read 2 more answers
Find the sum of the following series
vazorg [7]

Answer:

a) 820

b)450

c)  -540

d) -294

e) 1440

f) 1425

Step-by-step explanation:

a) it is an arithmetic progression with ratio=4

   a1=3,

     a2=3+r=3+4=7.....

    a20=a1+19r

so a20=3+19*4=3+76=79

S=(a1+an)*n/2 where n=20

so S=(3+79)*20/2=820

b) a15=a1+14*r=2+14*4=2+56=58

S=(a1+a15)*15/2=(2+58)*15/2=60*15/2=30*15=450

It is the same formula for all  the exercises

S=(a1+an)*n/2 ,     where n is the number of terms

c) a40=30+39*(-3)=30-87=-57

So S=(30-57)*40/2=-540

d) a14=5+13*(-4)=5-52=-47

S=(5-47)*14/2=-42*14/2=-42*7=-294

e) it is 5+7+9+......+75

nr of  terms  = (an-a1) :r+1=(75-5):2+1=36

S=(5+75)*36/2=36*40=1440

f) ratio=7-4=3

the  same formula for n= (91-4):3+1=87:3+1=29+1=30

S=(4+91)*30/2=95*30/2=2850/2=1425

8 0
3 years ago
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