All categories

3 years ago

Help help help help

Mathematics

2 answers:

sergiy2304 [10]3 years ago

6 0

Try Helena. This is just a wild guess by the way so if i’m wrong dont get mad LOL.

liraira [26]3 years ago

3 0

Answer:

The correct answer is Helena

You might be interested in

Find the fourth term of the sequence given by the rule tn= -2(2)^n-1 A) 32 B) -32 C)-1 6 D) 16

BartSMP [9]

<h2>Answer: C)-16</h2>

Step-by-step explanation:

We have a sequence with the following rule:

$t_{(n)}=-2(2)^{n-1}$

This gives us the n term of the sequence. Now, if we want to find the fourth term, we have to substitute $n$ by 4:

$t_{(4)}=-2(2)^{4-1}$

$t_{(4)}=-2(2)^{3}$

$t_{(4)}=-2(8)$

Finally:

$t_{(4)}=-16$ This is the fourth term of the sequence

4 0

3 years ago

Jose wants to fence in his garden. The shape is a rectangle. Two sides are each 12 feet long. The other two sides are each 108 i

7nadin3 [17]

The answer is To your question is C

5 0

3 years ago

Radius is 9.4. What is circumference?

Ket [755]

C= pi x 2r
C=pi x diameter
D=2r

5 0

3 years ago

Find the length of AB

aniked [119]

FIRST QUESTION
Given points are:
A(2, -4) and B(6, 2)
Now, Use the distance formula.
distance formula = $\sqrt{ (x_{2}- x_{1})^{2} + ( y_{2} - y_{1} )^{2} }$

Now, plug the values into the formula, So,
distance = $\sqrt{ (6- 2)^{2} + ( 2 - (-4))^{2} }$

= $\sqrt{ (6- 2)^{2} + ( 2 +4))^{2} }$

= $\sqrt{ (4)^{2} + ( 6))^{2} }$

= $\sqrt{ 16+36}$

= $\sqrt{52}$

= $2 \sqrt{13}$

So, the length of AB is $2 \sqrt{13}$ .

<span>THIRD QUESTION
</span>Two points given are:
A(3, -2) and B(1, 1)
Also given that B is the midpoint of AC.

Let, the co-ordinates of C be C(a, b).
Now, using midpoint formula,
Midpoint = $(\frac{ x_{1}+ x_{2} }{2} , \frac{ y_{1}+ y_{2} }{2} )$

$(1, 1)=(\frac{ 3+ a }{2} , \frac{ -2+b }{2} )$

Now, equaling the ordered pair, we have,

$1=\frac{ 3+ a }{2}$ .............equation (1)

$1=\frac{ -2+b }{2}$ ................equation (2)

Now, taking equation (1)
$1=\frac{ 3+ a }{2}$

$1*2=3+a$

$2-3=a$

$a=-1$

Now, taking equation (2)
$1=\frac{ -2+b }{2}$

$1*2=-2+b$

$2+2=b$

$b=4$

<span>So, the co ordinates of C are (a, b) which is <u>(-1 , 4)

</u></span>
<span>SECOND QUESTION:
</span>Given equations are:
2x + 3y = 14.....................equation (1)
-4x + 2y = 4 .....................equation (2)
Taking equation (2)
-4x + 2y = 4
2y = 4 + 4x
y = (4 + 4x) / 2
y = 2 + 2x .......................equation (3)
Now, Taking equation (1)
2x + 3y = 14
Substituting the value of y from equation (3), we get,
2x + 3(2 + 2x) = 14
2x + 6 + 6x = 14
8x = 14 - 6
x = (14 - 6) / 8
x = 1

Taking equation (3)
y = 2 + 2x
Now, substituting the value of x in equation (3), we get,
y= 2 + 2 (1)
y = 2 + 2
y = 4

So, x=1 and y=4

6 0

3 years ago

A hot air balloon is flying at and altitude of 2101 feet. If the angle of depression from the pilot in the balloon to a house on

alekssr [168]

The problem is modelled as right angle triangle, shown in the diagram below

The distance between the pilot and the house is labelled as $x$

Using the trigonometry ratio of sine
$sin(31)= \frac{opposite}{hypotenuse}$
$sin(31)= \frac{2010}{x}$
$x= \frac{2101}{sin(31)} = 4079.3 ft$

3 0

3 years ago

Help help help help​

Help help help help