Joe added 1,500 liters of water to his pool. How many kiloliters did he add to his pool?
2 answers:
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Step-by-step explanation:
Given
To get g(x), we will have to integrate g'(x)
If g(1) = 0, this means at x = 1, g(x) = 0
0 = -1⁻¹ + C
C= 1
Substitute C = 1 into the function
g(x) = -x⁻¹ + 1
If g(2) = 0, this means at x = 2, g(x) = 0
0 = -2⁻¹ + C
C= 2⁻¹
C = 1/2
Substitute C = 2 into the function
g(x) = -x⁻¹ + 1/2