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3 years ago

This visual representation shows the sets of real numbers.

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

7 0

Answer:

All natural numbers are also whole numbers.

Step-by-step explanation:

Natural numbers are called counting numbers. They are numbers you can count. Although, Zero is not among them. Neither are negative numbers. Succinctly put, Natural numbers are numbers you can count with the exception of negative numbers and Zero.

Whole numbers are an extension of natural numbers. Unlike Natural numbers although, whole numbers contain Zero. Yet, like natural numbers, that do not contain negative numbers. As a result, we can call them counting numbers that includes Zero.

Now from the above definitions, we can see that

1, whole numbers and natural numbers have many numbers in common. So then, 1 is wrong.

2, all natural numbers are whole numbers, not some. So then, 2 is wrong

3, all whole numbers are not natural numbers, because Zero is a whole number, yet, it's not a natural number.

4, all natural numbers are whole numbers, and this is our answer.

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Damm [24]

Answer:

The margin of error for this estimate is of 14.79 yards per game.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.093

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample.

You randomly select 20 games and see that the average yards per game is 273.7 with a standard deviation of 31.64 yards.

This means that $n = 20, s = 31.61$

What is the margin of error for this estimate?

$M = T\frac{s}{\sqrt{n}}$

$M = 2.093\frac{31.61}{\sqrt{20}}$

$M = 14.79$

The margin of error for this estimate is of 14.79 yards per game.

3 0

3 years ago

What is the area of a parallelogram if the coordinates of its vertices are (0, -2), (3, 2), (8,2), and (5,-2)?

Llana [10]

Answer:

The area of the parallelogram is 20 units²

Step-by-step explanation:

* Lets explain how to solve the problem

- The vertices of the parallelogram are (0 , -2) , (3 , 2) , (8 , 2) , (5 , -2)

- The side joining the points (0 , -2) and (5 , -2) is a horizontal side

because the points have same y-coordinates

- The side joining the points (3 , 2) and (8 , 2) is a horizontal side

because the points have same y-coordinates

∴ These two sides are parallel bases of the parallelogram

∵ The length of any horizontal side = x2 - x1

∴ The length of the side = 5 - 0 = 5 <em>or</em> 8 - 3 = 5

∴ The length of one base of the parallelogram is 5 units

- The height of this base is the vertical distance between these two

parallel bases

∵ The length of any vertical distance = y2 - y1

∵ y2 = 2 and y1 = -2 ⇒ the y-coordinates of the parallel bases

∴ The length of the vertical distance = 2 - (-2) = 2 + 2 = 4 units

∵ This vertical distance between the two parallel bases is the height

of these bases

∴ The height of the parallelogram is 4 units

- The area of the parallelogram = base × height

∵ The base = 5 units and the height = 4 units

∴ The area = 5 × 4 = 20 units²

* The area of the parallelogram is 20 units²

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