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Find the distance points p (3,6) and q (7,3) to the nearest tenth?

Vladimir79 [104]

<h3>Answer: 5</h3>

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One method is to plot the points P(3,6) and Q(7,3) on the same xy grid. Plot a third point R at (3,3). See the diagram below.

A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.

a^2+b^2=c^2

3^2+4^2 = c^2

9+16 = c^2

c^2 = 25

c = sqrt(25)

c = 5

This is the length of PQ

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Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).

$d = \text{Distance from P to Q}\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(3-7)^2+(6-3)^2}\\\\d = \sqrt{(-4)^2+(3)^2}\\\\d = \sqrt{16+9}\\\\d = \sqrt{25}\\\\d = 5\\\\$

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3 years ago

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The plan for the Thorne’s backyard play area, shaped like a trapezoid, is shown. The area of the play area is 286.56 square feet

lorasvet [3.4K]

The length of material needed for the border is the perimeter of the backyard play area

<h3>How to calculate the length of material needed </h3>

The area of the play area is given as:

$Area = 286.56$

The area of a trapezoid is calculated using:

$Area = 0.5 * (L1 + L2) * H$

Where L1 and L2, are the parallel sides of the trapezoid and H represents the height.

The given parameter is not enough to solve the length of material needed.

So, we make use of the following assumed values.

Assume that the parallel sides are: 25 feet and 31 feet long, respectively.

While the other sides are 10.2 feet and 8.2 feet

The length of material needed would be the sum of the above lengths.

So, we have:

$Length = 25 + 31 + 10.2 + 8.2$

$Length = 74.4$

Using the assumed values, the length of material needed for the border is 74.4 feet