Find the t-value such that the area left of the t-value is 0.01 with 8 degrees of freedom.

Please help with these questions and show how u found them! i will mark brainliest !

Georgia [21]

Answer:

Step-by-step explanation:

Question 3

5 (k + 4) - 2k

Use distributive property of multiplication.

5k + 20 -2k

Combine like terms to get your answer.

3k +20

Question 4

2 (3 + d - 1)

Simplify the expression in the parenthesis.

2 (2 + d)

Use distributive property of multiplication.

4 + 2d

If you wanted it to be accepted at higher levels, switch the terms around.

2d + 4

7 0

3 years ago

Write an explicit formula for An, the nth term of the sequence 7, -42, 252, ....

erik [133]

Answer:

$A_n = 7(-6)^{n-1}$

Step-by-step explanation:

Key skills needed: Explicit formula, Geometric sequence

1) This is a geometric sequence, meaning a constant (like 6 or 3.5) is being multiplied to every term. First we need to find the constant.

This can be done by doing -42 ÷ 7 or 252 ÷ -42

-42 ÷ 7 equals -6.

252 ÷ -42 also equals -6.

2) This means that constant is -6.

3) The general form for an explicit formula of a geometric sequence is:

$a_n = a_1(r)^{n-1}$

--> r means the constant (or common ratio) that is being multiplied.

--> $a_1$ means the first term

--> $a_n$ means the "nth" numbered term (so $a_3$ is the 3rd term, $a_{10}$ is the 10th term and so on).

--> $n-1$ is just the "n" in $a_n$ minus 1.

4) We can use this formula to create an explicit formula for the geometric sequence in the problem.

--> $r = -6$ (Since we got -6 as the constant/common ratio).

--> $a_1 = 7$ (Since 7 is the 1st term)

This means that our formula would be --> $A_n = 7(-6)^{n-1}$

Hope you understood and have a nice day!! :D

8 0

3 years ago

Plz help

LiRa [457]

5*x-2=4 or you could put it as 5x-2=4

8 0

3 years ago

Solve x2 + 10x + 7 = 0 by completing the square. Which equation is used in the process?

BaLLatris [955]

$x^2+10x+7=0\ \ \ \ |subtract\ 7\ from\ both\ sides\\\\x^2+2x\cdot5=-7\ \ \ |add\ 5^2\ to\ both\ sides\\\\x^2+2x\cdot5+5^2=-7+5^2\ \ \ |use\ a^2+2ab+b^2=(a+b)^2\\\\(x+5)^2=-7+25\\\\(x+5)^2=18\iff x+5=\pm\sqrt{18}\\\\x+5=-\sqrt{18}\ or\ x-5=\sqrt{18}\\\\x+5=-\sqrt{9\cdot2}\ or\ x-5=\sqrt{9\cdot2}\\\\x+5=-\sqrt9\cdot\sqrt2\ or\ x-5=\sqrt9\cdot\sqrt2\\\\x+5=-3\sqrt2\ or\ x-5=3\sqrt2\ \ \ |subtract\ 5\ from\ both\ sides\\\\\boxed{x=-5-3\sqrt2\ or\ x=-5+3\sqrt2}$