Answer:
the second law states that the force F is the product of an object's mass and its acceleration a: F = m * a. For an external applied force, the change in velocity depends on the mass of the object.
Answer:
953.5 J/kg.°C
Explanation:
From the question,
Heat lost by the metal = heat gained by the glass.
cm(t₁-t₃) = c'm'(t₃-t₂)................. Equation 1
Where c = specific heat capacity of the metal, m = mass of the metal, c' = specific heat capacity of the glass, m' = mass of the glass, t₁ = initial temperature of metal, t₂ = initial temperature of glass, t₃ = Equilibrium temperature
Make c' the subject of the equation
c' = cm(t₁-t₃)/m'(t₃-t₂)................ Equation 2
Given: m = 5 kg, c = 650 J/kg.°C, m' = 1.25 kg, t₁ = 80 °C, t₂ = 20 °C, t₃ = 63.9 °C
Substitute these values into equation 2
c' = 5×650(80-63.9)/1.25(63.9-20)
c' = (5×650×16.1)/(1.25×43.9)
c' = 52325/54.875
c' = 953.5 J/kg.°C
Radiation helps chicken eggs warm. (The eggs need to be kept at a warm temperature so the chicks can be born naturally and safely).
F = 0.06N. Since the charges has different signs the force of atraction between them is 0.06N.
In order to solve this exercise we have to use Coulomb's Law equation which says that the magnitude of each of the electric forces with which two point charges at rest interact is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them. Given by the equation:
. Where k is the Coulomb's Constant
, q1 and q2 are the charges value in Coulomb (C), and d is the distance between charges in meters (m).
There are two balloons of charges +3.37 x 10-6 C and –8.21 x 10-6 C. The distance between the two balloons is 2.00 m. Calculate the force between the two ballons.

Answer:
The compression in the spring is 5.88 meters.
Explanation:
Given that,
Mass of the car, m = 39000 kg
Height of the car, h = 19 m
Spring constant of the spring, 
We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

x is the compression in spring

So, the compression in the spring is 5.88 meters.