Answer:
953.5 J/kg.°C
Explanation:
From the question,
Heat lost by the metal = heat gained by the glass.
cm(t₁-t₃) = c'm'(t₃-t₂)................. Equation 1
Where c = specific heat capacity of the metal, m = mass of the metal, c' = specific heat capacity of the glass, m' = mass of the glass, t₁ = initial temperature of metal, t₂ = initial temperature of glass, t₃ = Equilibrium temperature
Make c' the subject of the equation
c' = cm(t₁-t₃)/m'(t₃-t₂)................ Equation 2
Given: m = 5 kg, c = 650 J/kg.°C, m' = 1.25 kg, t₁ = 80 °C, t₂ = 20 °C, t₃ = 63.9 °C
Substitute these values into equation 2
c' = 5×650(80-63.9)/1.25(63.9-20)
c' = (5×650×16.1)/(1.25×43.9)
c' = 52325/54.875
c' = 953.5 J/kg.°C
