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Scilla [17]
3 years ago
10

The atomic number is the number of _______ In an atom

Physics
2 answers:
Usimov [2.4K]3 years ago
6 0

Answer:

Proton

Explanation:

The atomic number is the number of proton

In an atom

Andrei [34K]3 years ago
5 0

Answer: Protons

Explanation: The atomic number is the number of protons that are in the nucleus of an atom. Each element on the periodic table is defined by the number of protons. In other words, the protons/atomic number determines what element it is. Protons carry a positive charge.

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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

f=12GHz=12\cdot 10^9 Hz is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

So the wavelength of the beam is

\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

y=\frac{m\lambda D}{a}

where

m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

a = 2.0 m is the aperture of the antenna (which corresponds to the width of the slit)

Substituting, we find

y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m

and so, the diameter is

d=2y = 750 m

B) 0.23 W/m^2

First we calculate the area of the surface of the microwave at a distance of 30 km. Since the diameter of the circle is 750 m, the radius is

r=\frac{750 m}{2}=375 m

So the area is

A=\pi r^2 = \pi (375 m)^2=4.42\cdot 10^5 m^2

And since the power is

P=100 kW = 1\cdot 10^5 W

The average intensity is

I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2

4 0
3 years ago
An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion
anyanavicka [17]

Answer:

attached below is the free body diagram of the missing  illustration

Initial kinetic energy of the electron = 3 eV

Explanation:

The conclusion that can be drawn about the kinetic energy of the electron is

E_{e} = E_{3}  - E_{1}

E_{e} = initial kinetic energy of the electron

E_{1} = -4 eV

E_{3} = -1 eV

insert the values into the equation above

E_{e} = -1 -(-4)  eV

   = -1 + 4 = 3 eV

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3 years ago
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This is True

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4 years ago
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Consider the third period of the periodic table. Which element has the smallest atomic radius?
Anettt [7]
According to periodic trends in the periodic table, the atomic radius decreases from left to right. 

In period three, the element with the smallest atomic radius would be the element in the rightmost area. Protons increase as it goes to the right, which would mean they pull in electrons closer which decreases the size. 

So in period 3, the element with the smallest atomic radius is Argon (Ar). 
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