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3 years ago

The atomic number is the number of _______ In an atom

Physics

2 answers:

Usimov [2.4K]3 years ago

6 0

Answer:

Proton

Explanation:

The atomic number is the number of proton

In an atom

Andrei [34K]3 years ago

5 0

Answer: Protons

Explanation: The atomic number is the number of protons that are in the nucleus of an atom. Each element on the periodic table is defined by the number of protons. In other words, the protons/atomic number determines what element it is. Protons carry a positive charge.

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A pendulum has a period of 1.69 s on earth. what is its period on mars, where the acceleration of gravity is about 0.37 that on

love history [14]

The formula for the period of the pendulum is
$T=2 \pi \sqrt{ \frac{L}{g} }=$
where L is the pendulum's length and g the gravitational acceleration.

Labeling with E the Earth and with M Mars, we can write the period of the pendulum on Earth as
$T_E = 2 \pi \sqrt{ \frac{L}{g_E} }$
and the period of the pendulum on Mars as
$T_M = 2 \pi \sqrt{ \frac{L}{g_M} }$

if we calculate the ratio, we get
$\frac{T_M}{T_E}= \sqrt{ \frac{g_E}{g_M} }$
but we know that the gravitational acceleration on Mars is 0.37 times the gravitational acceleration on Earth:
$g_M = 0.37 g_E$
Substituting into the formula, we find
$\frac{T_M}{T_E}= \sqrt{ \frac{1}{0.37} }=1.64$
And so, the period of the pendulum on Mars is
$T_M = 1.64 T_E = 1.64 (1.67 s)=2.78 s$

8 0

3 years ago

Read 2 more answers

Describe what happens when u mix hot water with cold

svetoff [14.1K]

The hot immediately increase the temperature of the cold water until they both reach equilibrium state.

6 0

3 years ago

Lily replicates an experiment that found that the number of calories in a particular food is 50 kcal. She obtained data from fiv

goldenfox [79]

Incorrect i think! it’s definitely not accurate or precise

7 0

3 years ago

Two cars, A and B , travel in a straight line. The distance of A from the starting point is given as a function of time by xA(t)

OLga [1]

A) Car A is initially ahead

B) The two cars are at the same point at the times: t = 0, t = 2.27 s and

t = 5.73 s

C) The distance between the two cars is not changing at t = 1.00 s and t = 4.33 s

D) The two cars have same acceleration at t = 2.67 s

Explanation:

The position of the two cars at time t is given by the following functions:

$x_A(t) = \alpha t + \beta t^2$

with

$\alpha = 2.60 m/s\\\beta = 1.20 m/s^2$

Substituting,

$x_A(t)=2.60t+1.20 t^2$

And

$x_B(t)=\gamma t^2 - \delta t^3$

with

$\gamma=2.80 m/s^2\\\delta = 0.20 m/s^3$

Substituting,

$x_B(t)=2.80t^2-0.20t^3$

Here we want to find which car is ahead just after they leave the starting point. To find that, we just need to calculate the position of the two cars after a very short amount of time, let's say at t = 0.1 s. Substituting this value into the two equations, we get:

$x_A(0.1)=2.60(0.1)+1.20(0.1)^2=0.27 m$