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2 years ago

I do not understand this question

Mathematics

2 answers:

umka2103 [35]2 years ago

8 0

She’s right i guess

77julia77 [94]2 years ago

6 0

1. I think the underlined number is 2. So It will be hundredths.

2. (8 x 100) + (6 x 10) + (3 x 1) + (1/10) + (4/100) + (1/1000)

Or 800 + 60 + 3 + 0.1 + 0.04 + 0.001

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I haven’t really understood this yet

kakasveta [241]

A, F, and G.

The others have breaks in the range or don’t include all real numbers.

3 0

2 years ago

Graph triangle cuz with vertices x(-2, -4), y(2, -1), and z(4, -3) on the coordinate grid.

Vera_Pavlovna [14]

This is what I got pls mark me brainlest

4 0

2 years ago

P is the incenter of △JKL. Find m∠JKP. & can you please explain

dangina [55]

Answer:

m∠MKP = 35°

Step-by-step explanation:

Incenter is the intersection of angle bisectors.

∠MJP = ∠OJP, ∠MKP = ∠NKP, ∠NLP = ∠OLP

First find the value of x:

7x - 6 = 5x + 4
7x - 5x = 4 + 6
2x = 10
x = 5

Find the angle MJP:

7*5 - 6 = 29°

We know sum of interior angles of a triangle is 180°. Using this find the missing angle measure:

2*m∠MJP + 2*m∠NJP + 2*m∠MKP = 180°
m∠MJP + m∠NJP + m∠MKP = 90°
29° + 26° + m∠MKP = 90°
m∠MKP = 90° - 55°
m∠MKP = 35°

7 0

2 years ago

you run a business making birdhouses. you spend $600 to start your business, and it costs you $5.00 to make each birdhouse.

Alex787 [66]

Answer:

???

Step-by-step explanation:

What is the question?

4 0

3 years ago

Y is directly proportional to square root of x If y=56 when x=49 find, y when x=81

STALIN [3.7K]

$\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}$

$\stackrel{\begin{array}{llll} \textit{"y" directly}\\ \textit{proportional to }\sqrt{x} \end{array}}{y = k\sqrt{x}}\qquad \textit{we know that} \begin{cases} y = 56\\ x = 49 \end{cases}\implies 56=k\sqrt{49} \\\\\\ 56=7k\implies \cfrac{56}{7}=k\implies 8=k~\hfill \boxed{y=8\sqrt{x}} \\\\\\ \textit{when x = 81, what is "y"?}\hfill y=8\sqrt{81}\implies y=8(9)\implies y=72$

7 0

1 year ago