An add tape of 108 ft is incorrectly recorded as 100 ft resulting in a recorded 200-ft distance. what is the correct distance?

Is (-2,-4) a solution to the equation y=2x?

navik [9.2K]

Answer:

Yes, its a solution

Step-by-step explanation:

substitute -2 for x and -4 for y and see if its tru

-4=2(-2)

-4=-4 TRUE

3 0

4 years ago

Tenemos un rectángulo cuya área es (15n + 9nx) cm 2 y su base mide (3n) cm. Existe también un cuadrado con la misma altura del r

lana66690 [7]

Answer:

El área original del cuadrado es 34225 cm²

Step-by-step explanation:

Los parámetros dados son;

El área del rectángulo = (15·n + 9·n·x) cm²

La longitud de la base del rectángulo = (3·n) cm

La altura del cuadrado = La altura del rectángulo

El área original del cuadrado - 9·x² cm² = 1825 cm²

La altura del rectángulo = (El área del rectángulo) / (La longitud de la base del rectángulo)

∴ La altura del rectángulo = (15·n + 9·n·x) / (3·n) = 5 + 3·x

La altura del rectángulo = 5 + 3 · x = La altura del cuadrado

El área del cuadrado = Lado × Lado = Altura × Altura = (5 + 3·x) × (5 + 3·x)

∴ El área del cuadrado = (5 + 3·x) × (5 + 3·x) = 9·x² + 30·x + 25

Del área original del cuadrado - 9·x² cm² = 1825 cm², tenemos;

9·x² + 30·x + 25 - 9·x² = 1825

30·x + 25 = 1825

30·x = 1825 - 25 = 1800

x = 1800/30 = 60

x = 60

El área original del cuadrado - 9·x² cm² = 1825 cm²

El área original del cuadrado = 1825 cm² + 9·x² cm² = 1825 cm² + 9 × 60² cm² = 34225 cm²

El área original del cuadrado también se puede encontrar de la siguiente manera;

El área original del cuadrado = (5 + 3 × 60) × (5 + 3 × 60) = 34225 cm²

El área original del cuadrado = 34225 cm².

4 0

3 years ago

What is 3×3/4 and what is the strategy behind it

sergejj [24]

I believe the answer is 9.

7 0

3 years ago

Read 2 more answers

Lucy has a 40-inch T.V. This means the diagonal distance from one corner of the T.V. to the other is 40 inches.

masha68 [24]

Using Pathogorean Theorem.....

40 = the square root of 24^2 + 32^2
40 = the square root of 576 + 1024
40 = the square root of 1600
40 = 40

5 0

3 years ago

What line would be parallel to 8x-2y=7 with a point of 12,1

SOVA2 [1]

Answer:

$y = 4x - 47$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Parallel lines:

When two lines are parallel, they have the same slope.

8x-2y=7

Placing into the format, we have thtt:

$2y = 8x - 7$

$y = 4x - \frac{7}{2}$

Slope of 4.

This means that the desired line has the following equation:

$y = 4x + b$

Point of (12,1)

This means that when $x = 12, y = 1$

We use this to find b.

$y = 4x + b$

$1 = 48 + b$

$b = -47$

So, the line has the equation:

$y = 4x - 47$

7 0

3 years ago