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elena-14-01-66 [18.8K]
3 years ago
11

A manufacturing firm just received a shipment of 20 assembly parts, of slightly varied sizes, from a vendor. The manager knows t

hat there are only 15 parts in the shipment that would be suitable. He examines these parts one at a time.
a. Find the probability that the first part is suitable.
Mathematics
1 answer:
kaheart [24]3 years ago
6 0

Answer:

75% probability that the first part is suitable.

Step-by-step explanation:

A probability is the desired outcomes bivided by the number of total outcomes.

a. Find the probability that the first part is suitable.

Desired outcomes:

There are 20 parts, of which 15 are suitable, so D = 15

Total outcomes:

20 parts, so T = 20

Probability:

P = \frac{D}{T} = \frac{15}{20} = 0.75

75% probability that the first part is suitable.

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3 years ago
Jeannine needs to decide what size to make a rectangular
Harlamova29_29 [7]

Answer:

Total number of possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

Step-by-step explanation:

We are given that

Perimeter of rectangular garden=50 dm

Width is  even number.

Length is always longer than or equal to width.

Let length of rectangular garden=x

Width of  rectangular garden=y

We have to find the possible  number of combinations .

Perimeter of rectangular garden=2(x+y)

2(x+y)=50

x+y=50/2

x+y=25

If y=2 dm

x=25-2=23 dm

If y=4 dm

x=25-4=21 dm

If y=6 dm

x=25-6=19 dm

If y=8 dm

x=25-8=17 dm

If y=10 dm

x=25-10=15 dm

If y=12 dm

x=25-12=13 dm

If y=14 dm

x=25-14=11 dm

x<y

It is  not possible

Then, possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

5 0
3 years ago
If i have a forest composed of 25 species of trees, each with a known abundances, how many events are there in the sample space
Vsevolod [243]
There are 25 species of trees, each with a known abundances. The question is how many possible ways to randomly select one tree there are.
We should calculate the number of combinations. Combinations, because we select item/s from a collection. In this case, when we select only one item, the combination is also a permutation. From set of n objects we select r. In our case: n=25, r=1. 
The equation is: n!/r!(n-r)!= 25!/1!*24!=25*24!/24!=25
There are 25 different outcomes (events).
3 0
3 years ago
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