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SVETLANKA909090 [29]
3 years ago
6

What is wrong in this

Mathematics
1 answer:
il63 [147K]3 years ago
7 0
Step 3 is wrong ( = 1/10 pound x 1/10 pound )
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What is the slope of line PQ?
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Answer:

Step-by-step explanation:

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by the formula,

Slope = \frac{y_2-y_1}{x_2-x_1}

Slope of the line PQ passing through the two points P(-8, 2) and Q(4, 2) will be,

Slope 'm_1' = \frac{2-2}{-8-2} = 0

Therefore, slope of the line PQ parallel to the x-axis = 0

Slope of the line MN passing through the points M(8, 6) and N(8, -8) is,

Slope 'm_2' = \frac{6+8}{8-8} = ∞

Therefore, slope of the line MN parallel to y-axis is undefined.

Since, angle between the x-axis and y-axis is 90°,angle at the intersection  point between the lines parallel to x and y axis will be 90°.

These lines are perpendicular to each other.

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