All categories

3 years ago

Work out the gradient of a line that passes through co-ordinates (3,4) & (6,16).

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

4.33

Step-by-step explanation:

Given data

x1= 3

y1=3

x2=6

y2=16

M= y2-y1/x2-x1

substitute

M=16-3/6-3

M= 13/3

M=4.33

Hence the gradient is 4.33

You might be interested in

Please help me, will mark!!

BabaBlast [244]

Answer:

613 meters

Step-by-step explanation:

cos(50 degrees)=324/x

x*cos(50 degrees)=324

x=324/cos(50 degrees)

x=around 504.1

cos(35 degrees)=324/x

x*cos(35 degrees)=324

x=324/cos(35 degrees)

x=around 395.5

now lets find the distance in between the two people:

Distance from Shively to the tower

tan(50 degrees)=x/324

x=324*tan(50 degrees)

x= around 386.1

Distance from Sparzak to the tower

tan(35 degrees)=x/324

x=324*tan(35 degrees)

x=around 226.9

total distance=386.1+226.9=613 meters

8 0

3 years ago

Evaluate 4(a2 + 2b) - 2b when a = 2 and b = –2

amid [387]

First you simply have to substitute 2 in replace of all the a's, and -2 in replace of all of the b's

4((2)2+2(-2))

Then you want to follow the order of operations, PEMDAS (Parantheses-Exponent-Multiplication-Division-Addition-Subtraction), and multiply within the parantheses.

4(4+(-4))

Next you will add within the parantheses (So add the 4 and -4 together)

4(0)

Lastly multiply

0

Your answer is 0

Hope this helps!

5 0

4 years ago

Read 2 more answers

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

4 years ago

-4(n - 6) = 12 Solve the Equation.

Romashka-Z-Leto [24]

-4(n - 6) = 12

n - 6 = -12/4 divide both sides by -4

n - 6 = -3

n = -3 + 6 add both sides by 6

n = 3

hope that helps, God bless!

3 0

3 years ago

If F ( x ) = 2 x - 1, find the zero of F -1( x ). A) -1 B) 1/2 C) 1

tigry1 [53]

Answer:

Step-by-step explanation:

7 0

3 years ago

Work out the gradient of a line that passes through co-ordinates (3,4) & (6,16).​

Work out the gradient of a line that passes through co-ordinates (3,4) & (6,16).