What does a secondary consumer eat? Immersive Reader

What types of elements are shown in the polyatomic ions in model 1?

boyakko [2]

These ions are disjoint by the charge on the ion into four dissimilar tables and listed alphabetically within each table. Each polyatomic ion, has it called, chemical, formula, two dimensional drawing, and three dimensional representation are given.
The three dimensional buildings are drawn as CPK models. CPK structures represent the atoms as sphere, where the radius of the sphere is equal to the van der waals radius of the atom; these buildings give a measure up the volume of the polyatomic atom.

4 0

4 years ago

Initial mass of triphenyl methanol in g = 0.220g Initial volume of 33% HBr solution in ml = 0.60 ml Find mas of triphenyl bromid

tensa zangetsu [6.8K]

Answer:

0.792g of triphenyl bromide are produced.

Explanation:

The reaction of triphenyl methanol with HBr is:

triphenyl methanol + HBr → Triphenyl bromide.

Reaction (1:1), 1 mole of HBr reacts per mole of triphenyl methanol.

To know the mass of triphenyl bromide assuming a theoretical yield (Yield 100%) we need to find first limiting reactant:

Moles triphenyl methanol (Molar mass: 260.33g/mol) =

0.220g × (1mol / 260.33g) = 8.45x10⁻³ moles Triphenyl methanol

Moles HBr (Molar mass: 80.91g/mol; 33%=33g HBr/100mL) =

0.60mL ₓ (33g / 100mL) ₓ (1mol / 80.91g) = 2.45x10⁻³ moles HBr

As amount of moles of HBr is lower than moles of triphenyl methanol, HBr is limiting reactant.

As HBr is limiting reactant, moles produced of triphenyl bromide = moles HBr = 2.45x10⁻³ moles

As molar mass of triphenyl bromide is 323.2g/mol, mass of triphenyl bromide is:

2.45x10⁻³ moles × (323.2g / mol) =

<h3>0.792g of triphenyl bromide are produced.</h3>

5 0

4 years ago

HERES TWO, IF YOU GET THEM BOTH RIGHT, I'LL GIVE YOU BRAINLEST!!

guapka [62]

Answer:

no idea buddy

Explanation: no idea

5 0

3 years ago

Read 2 more answers

Write a net ionic equation to show how quinoline, c9h7n, behaves as a base in water.

Natalija [7]

Quinoline, $C_{9}H_{7}N$ acts a Bronsted-Lowry base as it can accept a proton, $H^{+}$ from water to form the conjugate base, $C_{9}H_{7}NH^{+}$ . This reaction can be represented as,

$C_{9}H_{7}N(aq)+H_{2}O(l) C_{9}H_{7}NH^{+}(aq)+OH^{-}(aq)$

Here in the reaction, the weak base quinoline accepts a proton $H^{+}$ from water to form the conjugate base of quinoline, $C_{9}H_{7}NH^{+}$ and hydroxide ion, $OH^{-}$

Therefore the net ionic equation to show the basic nature of quinoline in water is,

$C_{9}H_{7}N(aq)+H_{2}O(l) C_{9}H_{7}NH^{+}(aq)+OH^{-}(aq)$

4 0

3 years ago

A 3.00-l flask is filled with gaseous ammonia, nh3. the gas pressure measured at 26.0 ∘c is 1.55 atm . assuming ideal gas behavi

Phantasy [73]

Answer: -

A 3.00-l flask is filled with gaseous ammonia, NH₃. the gas pressure measured at 26.0 ∘c is 1.55 atm . assuming ideal gas behavior, 3.23 grams of ammonia are in the flask

Explanation: -

Volume V = 3.00 L

Pressure P = 1.55 atm

Temperature T = 26.0 °C + 273 = 299 K

We know the value of Universal gas constant R = 0.082 L atm K−1

mol−1

We use the ideal gas equation

PV = nRT

Number of moles of Ammonia n = $\frac{PV}{RT}$

= $\frac{1.55 atm x 3.00 L}{0.082 L atm K−1
 x 299 K}$

= 0.19 mol

Molar mass of NH₃ = 14 x 1 + 1 x 3 = 17 g / mol

Mass of NH₃ = Molar mass of NH₃ x number of moles of NH₃

= 17 g / mol x 0.19 mol

= 3.23 g

3 0

3 years ago