The ordered pair is included in the solution set to the following system is (0,2)
<h3>Set of inequalities</h3>
Given the set of inequalities
y > x2 + 1
y < x2 – x + 1
Equate both expressions to have:
x^2 + 1 = x^2 - x +1
1 = -x + 1
x = 0
Substitute x = 0 into any of the function
y = x^2 + 1
y = 1
This shows that the ordered pair is included in the solution set to the following system is (0,2)
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Answer:
(-8,-2) (-4,6)
Step-by-step explanation:i just got the answer
Answer: D
Step-by-step explanation:
A. 3 + -7 < -4
-4 < -4
X
this one isn’t a solution
B. 3 + -7 ≤ -4
-4 ≤ -4
this works, let’s try the other equation
3(3) + 2(-7) < -5
9 + -14 < -5
-5 < -5
X
this one doesn’t work either, let’s go on to the next one
C. the first equation is the same as the first one in A, and that didn’t work, so we know that the whole thing doesn’t work and we don’t have to do any math
D. we know the first equation works because we did it in B
let’s go on to the second equation
3(3) + 2(-7) ≤ -5
9 -14 ≤ -5
-5 ≤ -5
this works, so that means that both equations work and the whole thing works :)
Answer: I know it 4 but I don’t know the equation for it, I can only help you this far.(hope it help)
Step-by-step explanation:
(1,4) and (-2,-8)
(x is the first number of the point which is 1 and -2, y is the second number of the point which is 4 and -8.)
(x1 is 1, it alway the first point they tell you on the problem like (1,-4) is on the problem first so it gonna be x1 and y1, for x2 it -2, it alway the second point in the problem like (-2,-8) is the second point they tell you so it gonna be y1 and y2.)
Do x2 - x1 and y2 - y1(y/x)
-8 - 4/-2 - 1 = -12/-3
-12/-3 divide top and bottom by -3, that would equal to 4
