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andrezito [222]
3 years ago
7

Find the greatest common factor of x^2y and xy^2

Mathematics
1 answer:
Dimas [21]3 years ago
6 0
1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
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It has been reported that men are more likely than women to participate in online auctions. In a recent survey, 65% of repondent
kupik [55]

Answer:

Hence, the Female and not participated is \frac{28}{100}=0.28\%

Step-by-step explanation:

Let Total respondents =100

Participated in online action (P)=65

Men (m)=45  and Women (F)=100-45=55

Male and participated (M\; \text{and}\;P)=38

Female and participated (F\; \text{and}\;P)=65-38=27

Male and not participated is 45-38=7

Female and not participated is 55-27=28

Therefore, the Female and not participated is \frac{28}{100}=0.28\%

Hence, the correct option is D.

5 0
3 years ago
Bill and Mary Ann went to the Viola bakery. Bill bought 5 pies and 7 donuts for ​$12.65. Mary Ann bought 6 of each for ​$12.30.
sweet [91]

Answer:

Pies=$0.85

Donuts= $1.20

Step-by-step explanation:

In the equation let p stand for the number of pies and d stand for the number of donuts.

To solve this set up 2 equations, one representing bill and the other representing Mary Ann.

  • Bill's equation is 5p+7d=$12.65.
  • Mary Ann's equation is 6p+6d=$12.30

Then solve using a system of equations. Systems of equations can be solved using elimination or substitution. I will use substitution. Solve bill's equation for p. This gives you p=\frac{12.65-7d}{5}. Then, you can substitute that into Mary Ann's equation. This looks like 6\cdot \frac{12.65-7d}{5}+6d=12.3. Solve for d. Once you solve d=1.20. Finally, substitute 1.20 back into either Bill's or Mary Ann's for d and solve for p. No matter which equation you use p=0.85.

3 0
2 years ago
Use substitution to solve the following system of equations. Show all of your work. Write the solution as an ordered pair.
trapecia [35]

Answer:

\left \{ {{x=2} \atop {y=2}} \right.

Step-by-step explanation:

Substitute the second equation into the first one:

4x+(2x-2)=10\\6x-2=10\\6x=12\\x=2

Substitute x=2 into the second equation:

y=2\times 2-2\\y=4-2\\y=2

\therefore \left \{ {{x=2} \atop {y=2}} \right.

3 0
1 year ago
Whoever checks my work and tell what I did wrong and the right answer will
gulaghasi [49]

Answer:

See below

Step-by-step explanation:

I believe that you only had to do letters F, H, and J. In that case, let's go over each one!

F: For isolatingd_{1}, we need to get rid of the 1/2 first. Let's multiply each side by 2:

2*m = 2*\frac{1}{2}(d_{1}+  d_{2}) \\2m = d_{1}+  d_{2}

After this, we just subtract d_{2} from each side to get d_{1}=2m- d_{2}. Dark Blue is correct! Let's now plug in those numbers below:

d_{1}=2(10)- 13 = 20-13=7

G: Let's isolate the vw^2 on one side by subtracting y from each side:

vw^{2} +y-y=x-y\\vw^{2}=x-y

Let's now divide each side by v, then put each side under a square root to get our final answer:

\frac{vw^2}{v} = \frac{x-y}{v}\\  w^2 =  \frac{x-y}{v}\\\sqrt{w^2} = \sqrt{\frac{x-y}{v}} \\w=\sqrt{\frac{x-y}{v}}

Orange is correct! Again, let's solve the problem underneath:

w=w=\sqrt{\frac{38-(-7)}{5}} = \sqrt{\frac{38+7}{5}} = \sqrt{\frac{45}{5}}=\sqrt{9}=3

H: This one has some stuff that we haven't worked with quite yet (like terms), but our approach is the same: isolate c on one side of the equation.

2a-2a+3c=17a-2a+21\\3c = 15a+21\\\frac{3c}{3} = \frac{15a+21}{3}\\c = \frac{15a}{3}+ \frac{21}{3} \\c = 5a+7

Purple is correct! Let's solve the problem:

c = 5(\frac{16}{5})+7 = 16+7 = 23

7 0
2 years ago
I really need help with this please helpp!!!
jolli1 [7]
What do you need help in??
6 0
2 years ago
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