Find the greatest common factor of x^2y and xy^2
1 answer:
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Answer:
Ratio = 3 : 2 and value of m = 5.
Step-by-step explanation:
We are given the end points ( -3,-1 ) and ( -8,9 ) of a line and a point P = ( -6,m ) divides this line in a particular ratio.
Let us assume that it cuts the line in k : 1 ratio.
Then, the co-ordinates of P = .
But, = -6
i.e. -8k-3 = -6k-6
i.e. -2k = -3
i.e.
So, the ratio is k : 1 i.e i.e. 3 : 2.
Hence, the ratio in which P divides the line is 3 : 2.
Also, = m where
i.e. m =
i.e. m =
i.e. m =
i.e. m = 5.
Hence, the value of m is 5.
Answer:
The cost of tuition as a function of x, the number of years since 1990, is C(x)= 14*(x-1990) + 95
Step-by-step explanation:
A linear function is a polynomial function of the first degree that has the following form:
y= m*x + b
where
- m is the slope of the function
- n is the ordinate (at the origin) of the function
So, in this case: C(x)= m*( x-1990) + b where x is the number of years since 1990.
Given the coordinates of two points, it is possible to determine the slope m of the line from them using the following formula:
In this case, you know that in 1990, the cost of tuition at a large Midwestern university was $95 per credit hour. And in 1999, tuition had risen to $221 per credit hour. So:
- x1= 1990
- y1= 95
- x2= 1999
- y2= 221
So the value of m is:
m= 14
So C(x)= 14*( x-1990) + b. In 1999, tuition had risen to $221 per credit hour. Replacing:
221= 14*(1999 - 1990) + b
221= 14*9 +b
221= 126 + b
221 - 126= b
95= b
Finally, <u><em>the cost of tuition as a function of x, the number of years since 1990, is C(x)= 14*(x-1990) + 95</em></u>