A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
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Answer:
No, it is not a right triangle.
Step-by-step explanation:
If the triangle was a right triangle, then the Pythagorean Theorem states that a^2 + b^2 = c^2. Let's test it on this triangle:
13^2 + 14^2 = 365, or c^2. If this is a right triangle, c should equal 15.
However, sqrt(365) = 19.1, which is not 15. So, the triangle is not a right triangle.
Answer:
x = -1/2
Step-by-step explanation:
(x - 4) * 2 = -9
Divide both sides by 2:
x - 4 = - 9 / 2
Add 4 to both sides:
x = - 1 / 2.
It mean that everything is goin down and that there isnt anything interfering with it
