It’s would be 12.75 because when you add the 1 grandstand, 2 bleachers and the 3 box seats you get 47.25 and 60-47.25=12.75.
<u>Options</u>
![(A)\left(-\infty , \dfrac23\right]\\\\(B)\left(-\infty , \dfrac23\right) \\\\(C)(\frac23\right, \infty ) \\\\(D) [\frac23\right, \infty )](https://tex.z-dn.net/?f=%28A%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%5D%5C%5C%5C%5C%28B%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%29%20%5C%5C%5C%5C%28C%29%28%5Cfrac23%5Cright%2C%20%5Cinfty%20%29%20%5C%5C%5C%5C%28D%29%20%5B%5Cfrac23%5Cright%2C%20%5Cinfty%20%29)
Answer:
Step-by-step explanation:
Given the solution to an inequality
{x|x>2/3}
The solution set does not include 
, therefore, it must be open at the left. Recall that we use a curvy bracket ( to denote openness at the left.
Since x is greater than , the solution set contains all values of larger than up till infinity. Since infinity is an arbitrarily large value, we also use an open bracket at the right.
Therefore, another way to represent the solution {x|x>2/3} is:
The correct option is C.
F(x)=3x+1 (preimage)
g(x)=x+1 (image)
it is undergoing a reduction/compression with translation.
In general, a linear transformation is
g(x) = a*f(bx-h)+k
h=horizontal translation (right if h>0, left if h<0, note formula has minus sign)
k=vertical translation (up if k>0, down if k<0)
a=vertical stretching, (stretching if |a|>1, compression if |a|<1, also, if a<0, a reflection across the x-axis is performed)
b=horizontal stretching (|b|>0 compression, |b|<0 stretching, also, if b<0, a reflection across the y-axis is performed)
In this case,
g(x)=f(x/3), so it is a horizontal stretching.
Note that the y-intercept remains unchanged.
Answer:
Try ABECFDGHI
Step-by-step explanation:
Im going FROM left to right
