Answer:
N, which is the increment is 4
Answer:
![\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D%5Ccdot%5Csqrt%5B3%5D%7B5%7D%20%3D%5Csqrt%5B6%5D%7B5%5E3%7D%20%5Ccdot%5Csqrt%5B6%5D%7B5%5E2%7D%20%3D%5Csqrt%5B6%5D%7B5%5E5%7D%20%3D5%5E%7B%285%2F6%29%7D)
Step-by-step explanation:
The rules of exponents apply, even when they are fractional exponents:
![a^b\cdot a^c=a^{b+c}\\\\\sqrt[b]{x^a}=x^{(a/b)}](https://tex.z-dn.net/?f=a%5Eb%5Ccdot%20a%5Ec%3Da%5E%7Bb%2Bc%7D%5C%5C%5C%5C%5Csqrt%5Bb%5D%7Bx%5Ea%7D%3Dx%5E%7B%28a%2Fb%29%7D)
All these cases represent experiments whose outcomes are all equaly likely. What we mean is that the cards have all the same probability of being dealt (1/52), and all the spaces of the spinner have the same probability of being landed into (1/5).
These probabilities are computed as 1 over all the possible outcomes.
(a) If you want a heart card and a five, you want the 5 of hearts. So, only one card would satisfy your request, and thus you have probability 1/52 of dealing the 5 of hearts.

(b) There are four 10s and four Jacks in the deck, so 8 cards satisfy your request. With probability 8/52, you'll be dealt a Jack or a 10.

(c) You have two "good" outcomes out of 5, so your probability is 2/5.

Answer: Yes, it's possible
Step-by-step explanation:
53+118+9=180
The correct answer is C. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 5, 0, 3. Column 2 is labeled y with entries negative 18, negative 2, 10.
Explanation:
The purpose of an equation is to show the equivalence between two mathematical expressions. This implies in the equation "–2 + 4x = y" the value of y should always be the same that -2 + 4x. Additionally, if a table is created with different values of x and y the equivalence should always be true. This occurs only in the third option.
x y
5 -18
0 -2
3 10
First row:
-2 + 4 (5) = y (5 is the value of x which is first multyply by 4)
-2 + 20 = -18 (value of y in the table)
Second row:
-2 + 4 (0) y
-2 + 0 = -2
Third row:
-2 + 4 (3) = y
-2 + 12 = 10