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Kobotan [32]
3 years ago
13

HELP PLS HELP PLS HELP PLS HELP PLS HELP PLS HELP PLS HELP PLS HELP PLS ASAP THANK YOU VERY MUCH

Mathematics
2 answers:
sukhopar [10]3 years ago
6 0
I belive it is 28
I hope this helps you
stiks02 [169]3 years ago
5 0
It is 28 hope it helps:))))
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Solve by factoring:<br><br>x^2+4x-12=0
Alika [10]
X^2+4x-12=0
(x+6)(x-2)=0
X can equal -6 and 2.

x=-6
x=2
8 0
4 years ago
0.25÷3=x÷1 1/2 That fraction is one and a half.
Sladkaya [172]

Answer:

<h2>x = 1/8</h2>

Step-by-step explanation:

Given the expression 0.25÷3=x÷1 1/2, we are to look for the value of x from the given equation. Rewriting the equation we will have;

\dfrac{0.25}{3} = \dfrac{x}{1\frac{1}{2} }

On simplification;

0.25 * \frac{1}{3} = x * \frac{2}{3} \\ \\ \frac{25}{100}*\frac{1}{3} =\frac{2x}{3}\\\\ \frac{1}{4} *  \frac{1}{3} = \frac{2x}{3}\\\\ \frac{1}{12} = \frac{2x}{3}\\\\cross \ multiply\\\\2x * 12 = 3\\\\24x = 3\\\\Divide \ both \ sides \ by \ 24\\\\24x/24 = 3/24\\\\x = 1/8

Hence the value of x in the expression is 1/8

6 0
3 years ago
Please help me with this question
DochEvi [55]
Okay Bright, so the central angle is 36 degrees, so according to the formula you have on the top of the screen, we have to do 36/360, which is 1/10 or 0/1. 

Then we multiply that by the radius squared. 12^2 = 144. 

Finally, we multiply 144 by 0.1, which is 14.4. So our answer is H. 14.4\pi.

Notice that we don't multiply the radius squared by \pi, since the answers are in terms of \pi.

Hope this helped!
6 0
3 years ago
102+6⋅7+8<br><br> A- 70<br> B- 142<br> C- 150<br> D- 190
Mrrafil [7]
The answer is 152 because 102+8= 110 and 6 Times 7 is 42 and 42+110 = 152 so the answer choices are wrong
5 0
3 years ago
Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.
valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}

On the other hand, the distance form P to B is equal to d(P,B)=\sqrt{(x-4)^2+(y-1)^2+(z-(-1))^2}=\sqrt{(x-4)^2+(y-1)^2+(z+1)^2}

P is equidistant from A and B if and only if P satisfies the equation d(P,A)=d(P,B), that is,

\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-4)^2+(y-1)^2+(z+-1)^2}

Take the square in both sides of this equation to get

(x+3)^2+(y-6)^2+(z-3)^2=(x-4)^2+(y-1)^2+(z+1)^2

(x+3)^2-(x-4)^2+(y-6)^2-(y-1)^2+(z-3)^2-(z+1)^2=0

You can simplify using difference of squares and multiplying like this:

(7)(2x-1)+(-5)(2y-7)+(-4)(2z-2)=0

14x-10y-8z+36=0

which is the equation of a plane.

4 0
4 years ago
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