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3 years ago

Factor the expression.

1 answer:

3 0

B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out. When you check B you get $k^{2} -5kf+10kf- 50f^{2}$ combine your like terms and you have your original expression of $k^{2} +5kf-50 f^{2}$

Hope that helps

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25 points + brainly please answer quick

TiliK225 [7]

Answer:

use the pythagoras theorem

Step-by-step explanation:

$4^{2} = 2^2 + (2\sqrt{3})^2\\ 16 = 4 + 12\\16 = 16\\hence they are the sides of right angled triangle$

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2 years ago

Read 2 more answers

How do you redraw a scale drawing with a new scale

rjkz [21]

Take measurements of what you want to draw, (e.g. a simple cube that is 100 cm x 100 cm x 100 cm.)
A full scale drawing would require you to draw the cube on a paper 100 cm x 100 cm x 100 cm.
If you want to 'scale', you would then redraw using new measurements. So, a 1/10 scale drawing would mean that you would redraw the cube on paper as 10 cm x 10 cm x 10 cm.
A 1/20 scale would be 5 cm x 5 cm x 5 cm. The same concept holds for all scale drawings.

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2 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

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3 years ago

Darlene wants to buy a sweater that originally cost 32$ it is on sale for 20% off. Sales tax is 6.75%. What is the final price o

AURORKA [14]

Answer:

Step-by-step explanation:

32 x 0.20 = $6.40

32 - 6.4 = $25.60

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25.6 + 1.738 = 27.338 ≈$27.34

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2 years ago

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