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sergey [27]
3 years ago
13

Factor the expression.

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0
B. (k+10f)(k-5f) you can tell in 2 ways.  1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D.  Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out.  When you check B you get k^{2} -5kf+10kf- 50f^{2} combine your like terms and you have your original expression of k^{2} +5kf-50 f^{2}

Hope that helps
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1. x²+2xy+y²<br>2. x²-8x+16<br>3. 16a⁴_24a²b²+9b​
ale4655 [162]

Answer:

1.(x+y)²

2. (x-4)²

3. (4a²-3b²)²

6 0
3 years ago
Can anyone tell me the area? I will give brainlist if I'm able to​
pantera1 [17]

Answer:

143 yds^2

Step-by-step explanation:

3 0
2 years ago
john ran 6 1/2 miles. Ben ran half the distance that John ran. Sara ran a total of 4.75 miles. What was the total distance combi
abruzzese [7]

John ran 6 1/2. Ben ran half of that, so he had run 3 1/4 and Sarah ran 4.75 miles. Add those up and you get 14.5

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5 0
2 years ago
WILL GIVE BRAINLIEST!!!!!
dimaraw [331]

1. f(x)=x²+10x+16

Use the formula to find the vertex = (-b/2a, f(-b/2a)) , here in the above equation a=1(As, a>0 the parabola is open upward), b=10. by putting the values.

-b/2a = -10/2(1) = -5

f(-b/2a)= f(-5)= (-5)²+10(-5)+16= -9

So, Vertex = (-5, -9)

Now, find y- intercept put x=0 in the above equation. f(0)= 0+0+16, we get point (0,16).

Now find x-intercept put y=0 in the above equation. 0= x²+10x+16

x²+10x+16=0 ⇒x²+8x+2x+16=0 ⇒x(x+8)+2(x+8)=0 ⇒(x+8)(x+2)=0 ⇒x=-8 , x=-2

From vertex, y-intercept and x-intercept you can easily plot the graph of given parabolic equation. The graph is attached below.

2. f(x)=−(x−3)(x+1)

By multiplying the factors, the general form is f(x)= -x²+2x+3.

Use the formula to find the vertex = (-b/2a, f(-b/2a)) , here in the above equation a=-1(As, a<0 the parabola is open downward), b=2. by putting the values.

-b/2a = -2/2(-1) = 1

f(-b/2a)= f(1)=-(1)²+2(1)+3= 4

So, Vertex = (1, 4)

Now, find y- intercept put x=0 in the above equation. f(0)= 0+0+3, we get point (0, 3).

Now find x-intercept put y=0 in the above equation. 0= -x²+2x+3.

-x²+2x+3=0 the factor form is already given in the question so, ⇒-(x-3)(x+1)=0 ⇒x=3 , x=-1

From vertex, y-intercept and x-intercept you can easily plot the graph of given parabolic equation. The graph is attached below.

3. f(x)= −x²+4

Use the formula to find the vertex = (-b/2a, f(-b/2a)) , here in the above equation a=-1(As, a<0 the parabola is open downward), b=0. by putting the values.

-b/2a = -0/2(-1) = 0

f(-b/2a)= f(0)= −(0)²+4 =4

So, Vertex = (0, 4)

Now, find y- intercept put x=0 in the above equation. f(0)= −(0)²+4, we get point (0, 4).

Now find x-intercept put y=0 in the above equation. 0= −x²+4

−x²+4=0 ⇒-(x²-4)=0 ⇒ -(x-2)(x+2)=0 ⇒x=2 , x=-2

From vertex, y-intercept and x-intercept you can easily plot the graph of given parabolic equation. The graph is attached below.

4. f(x)=2x²+16x+30

Use the formula to find the vertex = (-b/2a, f(-b/2a)) , here in the above equation a=2(As, a>0 the parabola is open upward), b=16. by putting the values.

-b/2a = -16/2(2) = -4

f(-b/2a)= f(-4)= 2(-4)²+16(-4)+30 = -2

So, Vertex = (-4, -2)

Now, find y- intercept put x=0 in the above equation. f(0)= 0+0+30, we get point (0, 30).

Now find x-intercept put y=0 in the above equation. 0=2x²+16x+30

2x²+16x+30=0 ⇒2(x²+8x+15)=0 ⇒x²+8x+15=0 ⇒x²+5x+3x+15=0 ⇒x(x+5)+3(x+5)=0 ⇒(x+5)(x+3)=0 ⇒x=-5 , x= -3

From vertex, y-intercept and x-intercept you can easily plot the graph of given parabolic equation. The graph is attached below.

5. y=(x+2)²+4

The general form of parabola is y=a(x-h)²+k , where vertex = (h,k)

if a>0 parabola is opened upward.

if a<0 parabola is opened downward.

Compare the given equation with general form of parabola.

-h=2 ⇒h=-2

k=4

so, vertex= (-2, 4)

As, a=1 which is greater than 0 so parabola is opened upward and the graph has minimum.

The graph is attached below.

5 0
3 years ago
Read 2 more answers
How do you write in words 4.110 and 4.10?
ohaa [14]

The <em>correct answers</em> are:

"Four and 11 hundredths" or "four and one hundred ten thousandths"; and

"Four and ten hundredths" or "four and one tenth."

Explanation:

In the first decimal, the digit 4 is in front of the decimal. This is read "Four and". After the decimal, we have 110. We look at the last place, digit, 0. Going by our place value, this is in the thousandths place. We read the block of digits 110 as "one hundred ten" and it is "thousandths." This makes the number "four and one hundred ten thousandths."

Alternatively, if we drop the zero, we would have 4.11. It is still "four and"; this time the last digit is 1, and it is in the hundredths place. 11 is read as "eleven", so this would be "four and eleven hundredths."

For the second number, 4.10, we have a 4 in front of the decimal, so we again have "four and". Our last digit is 0, and it is in the hundredths place; 10 is read "ten", so we have "four and ten hundredths."

Alternatively, if we drop the zero, we have 4.1. This is still "four and"; the 1 is now our last digit, and it is in the tenths place, so we have "four and one tenth."

8 0
3 years ago
Read 2 more answers
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