Answer/Step-by-step explanation:
1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:
Side CD and side DG.
2. Vertex of <2 is the endpoint at which two sides meet to form <2.
Vertex of <2 is D.
3. Another name for <3 is <EDG
4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.
5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.
6. m<5 = 42°
m<1 = 117°
m<CDF = ?
m<5 + m<1 = m<CDF (angle addition postulate)
42° + 117° = m<CDF (Substitution)
159° = m<CDF
m<CDF = 159°
7. m<3 = 73°
m<FDE = ?
m<FDG = right angle = 90°
m<3 + m<FDE = m<FDG (Angle addition postulate)
73° + m<FDE = 90° (Substitution)
73° + m<FDE - 73° = 90° - 73°
m<FDE = 17°
Answer:
i think its a 6/7 and 60/70
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
2
cos
(
x
)
−
1
=
0
3
x
=
4
−
x
x
−
5
=
−
3
Step-by-step explanation:
im am pretty sure it is b.sometimes because an equation can have more then one answer
Answer:
y = 3/2*x - 5
Step-by-step explanation:
Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:
P1=(x1,y1) and P2=(x2,y2)
slope formula ---> m=(y2-y1)/(x2-x1)
Replacing the given points ---> m=(1-4)/(4-6) = 3/2
then replacing the slope value obtained:
y = 3/2*x + b
Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:
1 = 3/2*4 + b
1 = 6 + b
1 - 6 = b
-5 = b
therefore the line equation is:
y = 3/2*x - 5
