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3 years ago

If right answer good review

Mathematics

1 answer:

Studentka2010 [4]3 years ago

8 0

Answer:

the slope of the line will change from positive to negative

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What is the length of arc LM?

il63 [147K]

Answer:

C. 9π/2

Step-by-step explanation:

<u>Full circle is:</u>

C = 2πr = 2π*6 = 12π

<u>Arc length of LM is:</u>

12π * (3π/4 ÷ 2π) =
12π*3/8 =
9π/2

Correct choice is C

4 0

3 years ago

What is the product of a monomial and a trinomial?

diamong [38]

Let m = monomial

Let t = trinomial

So, m times t = t.

monomial times a trinomial = another trinomial.

3 0

4 years ago

What happens to the value of the expression as 50/p decreases from a large positive number to a small positive number?

Pepsi [2]

Answer:

50/p increases from a small positive number to a big positive number.

Step-by-step explanation:

p is in the denominator. This means that p and the value of the expression 50/p are inverse proportional. So for a big value of p, 50/p has a small positive value. For a small value of p, 50/p has a high positive value.

what happens to the value of the expression 50/p as p decreases from a large positive number to a small positive number?

50/p increases from a small positive number to a big positive number.

For example

50/1000 = 0.05

50/1 = 50

7 0

3 years ago

Use a table of values to graph the function f(x) = x^2 - 4x +3

Vaselesa [24]

Here is my table of points:

8 0

3 years ago

Scientists discover two planets orbiting a distant star. The average distance from the star to Planet A is 4 AU, and it takes 43

Kitty [74]

Answer:

Option C - 9 AU

Step-by-step explanation:

To find : What is the average distance from Planet B to the star?

Solution :

According to kepler's law,

The squares of the sidereal periods (of revolution) of the planets are directly proportional to the cubes of their mean distances from the Sun.

i.e. $P^2\propto S^3$

We have given,

The average distance from the star to Planet A is $S_1=4$ AU.

It takes 432 Earth days for Planet A to orbit the star i.e. $P_1=432$

It takes 1,460 days for Planet B to complete an orbit i.e. $P_2=1460$

Substitute the values in $(\frac{P_1}{P_2})^2=(\frac{S_1}{S_2})^3$

$(\frac{432}{1460})^2=(\frac{4}{S_2})^3$

$0.0875=(\frac{4}{S_2})^3$

Taking root cube both side,

$\sqrt[3]{0.0875}=\frac{4}{S_2}$

$0.444=\frac{4}{S_2}$

$S_2=\frac{4}{0.444}$

$S_2=9.00$

The average distance from Planet B to the star is 9 AU.

Therefore, Option C is correct.

5 0

3 years ago