Step-by-step explanation:
divide 62 by 100 and then multiply that number by 66. I don't have a calculator on me rn sorry
Answer:
property tax on the house of $220,000 is $81,840
Step-by-step explanation:
Property tax on $92000 home is = $3,430
tax rate =
tax rate =
= 3.72 %
tax on $220,000 home will be
= 3.72 % of $220,000
= 0.0372 × $220,000
= $81,840
hence, the property tax on the house of $220,000 is $81,840.
One way: log(A)-log(B) = log(A/B) right?
So, log( x^2-9/(x+3))
Now x^2-9 = (x+3)*(x-3), and x^2-9/(x+3) = x-3,
so log(x^2-9)-log(x+3) = log(x-3),
Indeed for all x but for x = -3, but probably no one asks you about that detail?
Answer:
Step-by-step explanation:
Given that:
The sample mean
The standard deviation = 9
Population mean = 20
Null hypothesis:
Alternative hypothesis:
(a)
When Sample size = 10
t = 1.0541
Degree of freedom df:
df = n -1
df = 10 - 1
df = 9
P(value) for t = 1.0541 at df = 9:
P(value) = P(Z > 1.0541)
P(value) = 1 - P(< 1.0541)
P(value) = 1 - 0.8403
P(value) = 0.1597
There is no enough evidence to infer at the 5% significance since p-value is greater than the level of significance.
(b) When sample size = 30
t = 1.8257
Degree of freedom df:
df = n -1
df = 30 - 1
df = 29
P(value) for t = 1.8257 at df = 29:
P(value) = P(Z > 0.9609)
P(value) = 1 - P(< 0.9609)
P(value) = 1 - 0.9609
P(value) = 0.0391
There is enough evidence to infer that the mean is greater than 20 at the 5% significance level as the p-value is less than the significance level.
(c) When sample size = 50
t = 2.3570
Degree of freedom df:
df = n -1
df = 50 - 1
df = 49
P(value) for t = 2.3570 at df = 49:
P(value) = P(Z > 0.9888)
P(value) = 1 - P(< 0.9888)
P(value) = 1 - 0.9888
P(value) = 0.0112
There is enough evidence to infer that the mean is greater than 20 at the 5% significance level as the p-value is less than the significance level.