Answer:
The expressions which equivalent to 
are:
⇒ B
⇒ C
Step-by-step explanation:
Let us revise some rules of exponent
Now let us find the equivalent expressions of
A.
∵ 4 = 2 × 2
∴ 4 = 
∴ 
= 
- By using the second rule above multiply 2 and (n + 2)
∵ 2(n + 2) = 2n + 4
∴ = 
B.
∵ 4 = 2 × 2
∴ 4 = 2²
∴ = 2² × 
- By using the first rule rule add the exponents of 2
∵ 2 + n + 1 = n + 3
∴ =
C.
∵ 8 = 2 × 2 × 2
∴ 8 = 2³
∴ = 2³ × 
- By using the first rule rule add the exponents of 2
∵ 3 + n = n + 3
∴ =
D.
∵ 16 = 2 × 2 × 2 × 2
∴ 16 = 
∴ 
= ×
- By using the first rule rule add the exponents of 2
∵ 4 + n = n + 4
∴ = 
E.
is in its simplest form
The expressions which equivalent to are:
⇒ B
⇒ C
Answer:
(4, 9) is not a solution to 3(x + 2) = y.
Step-by-step explanation:
3(x + 2) = y
Substitute (4, 9) into the equation.
3(4 + 2) = 9
Add the inside of the parenthesis.
3(6) = 9
Multiply.
18 ≠ 9
Answer:
circle with center at (–5, 10), shading inside the circle
Step-by-step explanation:
edge2021
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer: C. Industrialization
Step-by-step explanation:
×
=