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ludmilkaskok [199]
2 years ago
7

Which of the following equations has infinitely many solutions? A. 2x + 5(2x + 6) = 12x + 30 B. 2x + 5 = 2 C. 2(x + 5) + 2 = 6x

+ 2(x + 2) D. 5x + 2 = 2x + 6
Mathematics
1 answer:
Nat2105 [25]2 years ago
8 0

Answer:

A. 2x + 5(2x + 6) = 12x + 30

Step-by-step explanation:

Infinitely many solutions means the two sides of the equation will be equal to each other, so B and D can be eliminated. Distribute for A and C to check

A. 2x + 5(2x + 6) = 12x + 30

    2x + 10x + 30 = 12x + 30

    12x + 30 = 12x + 30

C. 2(x + 5) + 2 = 6x + 2(x + 2)

    2x + 10 + 2 = 6x +2x + 4

     2x + 12 = 8x + 4

You only get the same equation for A, therefore A is the correct answer

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slope (m) = rate.    $40 per hour is the rate, so m = 45

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Answer: A


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3 years ago
Find the equation of the least squares regression line. Show all calculations, and be sure to define any variables used.
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Steps
Step 1: For each (x,y) point calculate x2 and xy.
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Step 5: Assemble the equation of a line.
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What is the volume, in cubic inches, of the right rectangular prism shown below?
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7 0
3 years ago
6 times the sum of 3 consecutive odd intergers is -18
Lyrx [107]
The answer: The 3 (three) consecutive odd integers are: -3, -1, 1.
_____________________________________________
Explanation:
_______________
To represent 3 (three consecutive odd integers):
____________________________________
Let "x" be the first odd integer.
____________________________________
Let "(x+2)" be next consecutive odd integer.
____________________________________
Let "(x+4") be the third odd integer.
____________________________________
The sum of these three consecutive odd integers:
__________________________________________
x + (x + 2) + (x + 4) = x + x + 2 + x + 4 = 3x + 6 ;
_________________________________________
Six ("6") times the sum of these 3 (three) consecutive odd integers =
_________________
6*(3x+6) = 6(3x + 6) = -18 (as given in the problem).
_____________________________________________
Given: 6(3x + 6) = -18 ; We can divide EACH SIDE of the equation by "6", to cancel the "6" on the left-hand side into a "1"; 
__________________________________________
{6(3x + 6) } / 6 = -18 / 6 ;  to get:
________________________________________
3x + 6 = -3 ; Now, we can subtract "6" from EACH SIDE of the equation:
__________________________________
3x + 6 - 6 = -3 - 6 ; to get:
__________________________________
3x = -9 ; Now, we can divide EACH SIDE of the equation by "3"; to isolate "x" on one side of the question; and solve for "x" ;
___________________________________
3x / 3 = -9 / 3 ;  x = - 3 ;
_____________________
Remember, from above:
__________________________
Let "x" be the first odd integer.  We know that "x = -3".
         Is this an odd integer? Yes!
____________________________________
Let "(x+2)" be next consecutive odd integer.  So (x+2) = (-3+2) = -1.
        Is this an odd integer? Yes!  Is this "{-1}" the next consecutive odd integer with respect to "{-3}"? Yes!
____________________________________
Let "(x+4") be the third odd integer. So (x+4) = (-3+4) = 1.
       Is this an odd integer? Yes!  Is this "{1"} the next consecutive odd integer with respect to "{-1}"? Yes!
___________________________
So, our 3 (three) consecutive odd integers are: -3, -1, 1.
___________________________
To check our work: Is 6 times the sum of our 3 consecutive odd integers, equal to "(-18)" ?

The sum of our 3 consecutive odd integers = -3 + (-1) + 1 = -3 - 1 + 1 = -3.

6 * -3 = ? -18? Yes!
___________________________





3 0
3 years ago
What is 19 divided by 4,257
antoniya [11.8K]
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8 0
3 years ago
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