$i^7 + \dfrac 1{i^4}\\\\=i^2 \cdot i^2 \cdot i^2 \cdot i + \dfrac 1{i^2 \cdot i^2}\\\\=(-1)(-1)(-1)i + \dfrac 1{(-1)(-1)} ~~~;[ i^2 = -1] \\\\\ = (-1)^3 i+ \dfrac 1{(-1)^2} \\\\=-i+1$

7 0

2 years ago

How do i convert -1 and 2/3 into a decimal?

hodyreva [135]

Step-by-step explanation:

-1 is already a decimal.

For any fraction you can use: 2/3=x/100

After that, you get x=approx 0.66...

7 0

1 year ago

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Which of the following is a solution of y - x < -3?

azamat

Answer:

Step-by-step explanation:

$Subtract- y- from- both -sides.\\-x (less than)-3-y\\2 Multiply both sides by -1.\\x (greater than ) 3+y$

5 0

3 years ago

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