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aev [14]
3 years ago
10

Which term of the arithmetic sequence 1, 5, 9, 13, ... is 169? It is the th term.

Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

43rd term

Step-by-step explanation:

Arithmetic sequences are basically linear functions, so the same value is added every time. So, knowing that Asub1 is equal to one, and Asubn is equal to 169 we can take 169-1 and divide by our common difference. This is four as 5-1=4 and 9-5=4.

So, (169-1)/4=42.

This is however 42 terms after Asub1, so this would be the 43rd teen of the sequence!

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4 0
3 years ago
I need help. I'm very confused.
Readme [11.4K]
Rounded to the nearest thousandth
3n = 3 (0.333) = 0.999 = 1
-n/3 = -0.333/ 3 = -0.111
2n = 2(0.333) = 0.666 = 0.667



8 0
3 years ago
D
mariarad [96]

Answer:

imma have to get back to u on that one

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3 years ago
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