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Alexeev081 [22]
3 years ago
15

Emily and Hunter tracked the average temperature in their city for the past 8 days. They recorded their temperature findings in

this list 66°F, 57°F, 61°F, 65°F, 54°F, 62°F, 59°F, 56°F
What is the mean absolute deviation of this data set?


Enter your answer in the box.​
Mathematics
1 answer:
lions [1.4K]3 years ago
7 0

Answer:

The mean absolute deviation = 3.5°F

Step-by-step explanation:

The sum of the given temperatures, ∑T, is found as follows;

∑T = 66°F + 57°F + 61°F + 65°F + 54°F + 62°F + 59°F + 56°F = 480°F

The number of days, n, over which the temperature was tracked = 8 days

Therefore, the mean, \bar x, of the data set = ∑T/n = 480°F/8 = 60°F

The mean absolute deviation is given by the following formula;

Mean \ absolute \ deviation = \frac{\sum \limits_{i = 1}^{n} \left | x_i - \bar x \right | }{n}

Therefore, we have;

66 - 60 = \left | 6\right | = 6

57 - 60 = \left | -3\right | = 3

61 - 60 =  \left | 1\right | = 1

65 - 60 =  \left | 5\right | = 5

54 - 60 =  \left | -6\right | = 6

62 - 60 =  \left | 2\right | = 2

59 - 60 =  \left | -1\right | = 1

56 - 60 =  \left | -4\right | = 4

The mean absolute deviation is therefore;

The mean absolute deviation = (6 + 3 + 1 + 5 + 6 + 2 + 1 + 4)/8 = 3.5°F.

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BartSMP [9]

Answer:

no

Step-by-step explanation:

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3 0
3 years ago
What are the solutions to the equation 2(x-3)^2=54 ?
erastova [34]

Answer:

      x =(6-√108)/2=3-3√ 3 = -2.196

 x =(6+√108)/2=3+3√ 3 = 8.196

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

2 • (x - 3)2 - 54 = 0

Step  2  :

 2.1    Evaluate :  (x-3)2   =  x2-6x+9 

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   2x2 - 12x - 36  =   2 • (x2 - 6x - 18) 

Adding  9  has completed the left hand side into a perfect square :

   x2-6x+9  =

   (x-3) • (x-3)  =

  (x-3)2  (x-3)1 =

   x-3

Now, applying the Square Root Principle to  Eq. #4.3.1  we get:

   x-3 = √ 27

Add  3  to both sides to obtain:

   x = 3 + √ 27

Since a square root has two values, one positive and the other negative

   x2 - 6x - 18 = 0

   has two solutions:

  x = 3 + √ 27

   or

  x = 3 - √ 27

Solve Quadratic Equation using the Quadratic Formula

 4.4     Solving    x2-6x-18 = 0 by the Quadratic Formula .

 According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

            - B  ±  √ B2-4AC

  x =   ————————

                      2A

  In our case,  A   =     1

                      B   =    -6

                      C   =  -18

Accordingly,  B2  -  4AC   =

                     36 - (-72) =

                     108

Applying the quadratic formula :

               6 ± √ 108

   x  =    —————

                    2

Can  √ 108 be simplified ?

Yes!   The prime factorization of  108   is

   2•2•3•3•3 

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 108   =  √ 2•2•3•3•3   =2•3•√ 3   =

                ±  6 • √ 3

  √ 3   , rounded to 4 decimal digits, is   1.7321

 So now we are looking at:

           x  =  ( 6 ± 6 •  1.732 ) / 2

Two real solutions:

 x =(6+√108)/2=3+3√ 3 = 8.196

or:

 x =(6-√108)/2=3-3√ 3 = -2.196

7 0
2 years ago
Urgent help needed...............
andreyandreev [35.5K]

Answer:

Option b is correct

\{x | x \neq \pm 7, x\neq 0\}.

Step-by-step explanation:

Domain is the set of all possible values of x where function is defined.

Given the function:

h(x) = \frac{9x}{x(x^2-49)}

To find the domain of the given function:

Exclude the values of x, for which function is not defined

Set denominator = 0

x(x^2-49) = 0

By zero product property;

x = 0 and x^2-49= 0

⇒x = 0 and  x^2 =49

⇒x = 0 and x = \pm 7

Therefore, the domain of the given function is:

\{x | x \neq \pm 7, x\neq 0\}

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3 years ago
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3 0
3 years ago
Please help me! if correct will mark brainliest
Wewaii [24]

Answer:

17.5

Step-by-step explanation:

formula:

y=k(x)

direct variation^^^

y=7, x=2

substitute it in the formula

7=(k)2 or 7=2k

7/2 or 3.5= k, k is the constant

now substitute k to the problem

y=5k

y=5(3.5)

y=17.5

3 0
2 years ago
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