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Alexeev081 [22]
3 years ago
15

Emily and Hunter tracked the average temperature in their city for the past 8 days. They recorded their temperature findings in

this list 66°F, 57°F, 61°F, 65°F, 54°F, 62°F, 59°F, 56°F
What is the mean absolute deviation of this data set?


Enter your answer in the box.​
Mathematics
1 answer:
lions [1.4K]3 years ago
7 0

Answer:

The mean absolute deviation = 3.5°F

Step-by-step explanation:

The sum of the given temperatures, ∑T, is found as follows;

∑T = 66°F + 57°F + 61°F + 65°F + 54°F + 62°F + 59°F + 56°F = 480°F

The number of days, n, over which the temperature was tracked = 8 days

Therefore, the mean, \bar x, of the data set = ∑T/n = 480°F/8 = 60°F

The mean absolute deviation is given by the following formula;

Mean \ absolute \ deviation = \frac{\sum \limits_{i = 1}^{n} \left | x_i - \bar x \right | }{n}

Therefore, we have;

66 - 60 = \left | 6\right | = 6

57 - 60 = \left | -3\right | = 3

61 - 60 =  \left | 1\right | = 1

65 - 60 =  \left | 5\right | = 5

54 - 60 =  \left | -6\right | = 6

62 - 60 =  \left | 2\right | = 2

59 - 60 =  \left | -1\right | = 1

56 - 60 =  \left | -4\right | = 4

The mean absolute deviation is therefore;

The mean absolute deviation = (6 + 3 + 1 + 5 + 6 + 2 + 1 + 4)/8 = 3.5°F.

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Show work please :)
fgiga [73]

Answer:

60

Step-by-step explanation:

90/100 = 54

Cross multiplying:

100 * 54 / 90

5400/90

60

4 0
2 years ago
Help asap please for brainlist !!!!!!!!!
IgorLugansk [536]
Bff i answered this earlier. It’s step 2!!! Because if you’re flipping the numerator and denominator, the sign of the exponent should be flipped as well. So the exponent will turn into -5x
Sorry if my previous answer was vague. #brainliest!!!
3 0
2 years ago
drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This mon
Kisachek [45]

Complete question is:

A large pool of adults earning their first drivers license includes 50% low- risk drivers, 30% moderate-risk drivers, and 20% high-risk drivers. Because these drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This month, the insurance company writes 4 new policies for adults earning their first drivers license. What is the probability that these 4 will contain at least two more high-risk drivers than low-risk drivers?

Answer:

probability that these 4 will contain at least two more high-risk drivers than low-risk drivers = 0.0488

Step-by-step explanation:

Let H represent High risk

M represent moderate risk

L represent Low risk.

The following combinations will satisfy the condition that there are at least two more high-risk drivers than low-risk drivers: HHHH, HHHL, HHHM, HHMM

The HHHH case has probability 0.2 ⁴ = 0.0016

The HHHL case has probability 4 × 0.2³ × 0.3 = 0.0096 (This is because L can be in four different places)

Similarly, the HHHM case has probability 4 × 0.2 ³ × 0.5 = 0.016

Lastly, the HHMM case has probability 6 × 0.2 ² × 0.3 ² = 0.0216 (This is because the number of ways to choose places for two M letters in this way is 6)

Summing all these probabilities, we have;

0.0016 + 0.0096 + 0.016 + 0.0216 = 0.0488

5 0
3 years ago
40 points! Brainliest for most helpful answer!
telo118 [61]

Answer:

the answer is in the image if you have any questions let me know

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP !!!!!!!!!! I'LL GIVE BRAINLIST!!!!!!
aleksandr82 [10.1K]
It is 189 the answer
5 0
2 years ago
Read 2 more answers
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