F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Let us consider the image on the left that is the image in which 1 and 2 , 3 and 4 are connected as image 1 and the other as image 2.
1. All Vertices are connected by the least amount of edges. True
2. Vertex 1 and 2 are not connected. This is false for image
1 and true for image 2
3. Vertex 3 and 4 are not connected. This is false for image
1 and true for image 2
4. You can get to Vertex 1 from Vertex 4 by going through Vertex 3. This is true for image 1
Step-by-step explanation:
2x = y-10
Rewrite as: 2x + 10 = y
Therefore:
2x+10 = y
2x +7 = 2y
Subtract the equations:
2x + 10 = y
- 2x + 7 = 2y
______________
3 = -y
Therefore y = -3
Substiture y = -3 into the second equation:
2x + 7 = 2(-3)
2x + 7 = -6
2x = -13
x= -6.5
Answer : (-6.5, -3)
