How many 2/3 are in 1?

Mathematics

2 answers:

Alinara [238K]3 years ago

5 0

Answer:

Um 1 if you mean 1/3 then 3

bekas [8.4K]3 years ago

5 0

Answer:

There is only one 2/3 in 1.

Step-by-step explanation:

so....when we divide 1 into three and take two out of it there is only one more fraction left. It totally depends on the question. We can also divide this 1/3 that is left into three more parts and take out two parts and write as 2/3 ......this can just go forever.....so we say there is only one 2/3 in 1.

You might be interested in

What is the next step to solve this equation?<br> 3x - 5 = 7

Ronch [10]

Answer:

Find the value of x the value is x=4

3x4=12

12-5=7

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
$=\dfrac{592\pi}{15}$