Answer:
Yes
Step-by-step explanation:
Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.
The solution may vary like Integers, rationals, irrationals or complex solutions.
To find two roots of the equation we can always use the formula given below to solve a quadratic equation,
For the quadratic equation,
, we have,
If the discriminant is greater than 
, we get complex roots.
Here is your answer:
Its scientific notations:
Its negative so your going to the left:
2.8×10^-4
=0.000028
X(30;0)
y(0;50)
substitue 0 for y and solve for x
substitute 0 in for x and solve for y
Most likely number 3
we can guess the average of the two since we don't have the time to actually add all of them and divide and number 3 describes it the most
You have to plug in 7 for f and 8 for k making it look like -5(7)-2+8-3(8), now multiply to get the further more, -35-2+8-24, now add or subtract to get -53
Hope this helps
