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3 years ago

PLEASE HELP! 30 POINT!!!

Mathematics

1 answer:

kow [346]3 years ago

5 0

Answer:

Step-by-step explanation:

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Suppose $7,558.20 in interest was earned after $12,350 was invested at a simple interest rate of 7.65%. How long (in years) was

vladimir1956 [14]

The formula is
I=prt
I interest earned 7558.20
P principle 12350
R interest rate 0.0765
T time?
Solve the formula for t by dividing both sides by pr to get
T=I/pr
T=7,558.20÷(12,350×0.0765)
T=8 years

Hope it helps!

5 0

3 years ago

A randomly generated list of integers from 0 to 7 is being used to simulate an

Misha Larkins [42]

Hi there!

$\large\boxed{\text{ C. } 25\%}}$

We have the numbers:

0 1 2 3 4 5 6 7

There are 8 total numbers, and 2 of those numbers (1 and 3) represent a success. Therefore:

$\text{p(success)} = \frac{\text{number of successes}}{total}\\\\\text{p(success)} = \frac{2}{8} = \frac{1}{4} = \boxed{25\%}$

6 0

3 years ago

5 times a number plus nine

Savatey [412]

Answer:

5x + 9

Step-by-step explanation:

when you dont know a number you are supposed to use a letter and when you want to multiply a letter and a number you put them next to each other then for this specific question you add 9

4 0

3 years ago

Please help! <br><br> ~I WILL MARK BRAINLIEST!~

myrzilka [38]

Answer:

his monthly fee is 0$

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The mayor is interested in finding a 95% confidence interval for the mean number of pounds of trash per person per week that is

baherus [9]

Answer:

(30.09, 32.91)

Step-by-step explanation:

Mean number of pounds of trash = x = 31.5 pounds

Standard deviation = s = 7.8 pounds

Sample size = n = 120

Confidence level = 95%

Since, we are given the sample standard deviation instead of the population standard deviation, we will use t-test to find the confidence interval.

Degrees of freedom = df = n - 1 = 120 - 1 = 119

The t-value associated with 95% confidence interval and df=119 from the t-table comes out to be:

t = 1.98

The formula to calculate the confidence interval is:

$(x-t\frac{s}{\sqrt{n}}, x+t\frac{s}{\sqrt{n}})\\$

Using the values in above expression we get:

$(31.5-1.98\times\frac{7.8}{\sqrt{120}}, 31.5+1.98\times\frac{7.8}{\sqrt{120}})\\\\ =(30.09,32.91)$

Thus, the 95% confidence interval for the mean number of lbs of trash per person per week that is generated in the city is (30.09, 32.91)

6 0

3 years ago