
<h3><u>Given </u><u>:</u><u>-</u></h3>
- A marker in the center of the fairway is 150 yards away from the centre of the green
- While standing on the marker and facing the green, the golfer turns 100° towards his ball
- Then he peces off 30 yards to his ball
<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>
<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>
Let assume that the distance between the golf ball and central of green is x
<u>Here</u><u>, </u>
- Distance between marker and centre of green is 150 yards
- <u>That </u><u>is</u><u>, </u>Height = 150 yards
- For facing the green , The golfer turns 100° towards his ball
- <u>That </u><u>is</u><u>, </u>Angle = 100°
- The golfer peces off 30 yards to his ball
- <u>That </u><u>is</u><u>, </u>Base = 30 yards
<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

- Here, a = perpendicular height
- b = base
- c = hypotenuse
- cos theta = Angle of cosine
<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>






Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards
Answer:
The length of BC = 12
Step-by-step explanation:
c^2 = a^2 + b^2
15^2 = 9^2 + b^2
225 = 81 + b^2
b^2 = 225 - 81
b^2 = 144
b = 12
The length of BC is 12
100x = 75.757575...
- x = 0.757575...
-----------------------------
99x = 75
x = 75/99
x = 25/33
Answer: 0.757575... = 25/33
It is (A). When removing decimal of 0.03 you will get = 3/100 so A is the correct answer.
Answer:
not statistically significant at ∝ = 0.05
Step-by-step explanation:
Sample size( n ) = 61
Average for student leader graduates to finish degree ( x') = 4.97 years
std = 1.23
Average for student body = 4.56 years
<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>
H0( null hypothesis ) : u = 4.56
Ha : u ≠ 4.56
using test statistic
test statistic ; t = ( x' - u ) / std√ n
= ( 4.97 - 4.56 ) / 1.23 √ 61
= 2.60
let ∝ = 0.05 , critical value = -2.60 + 2.60
Hence we wont fail to accept H0
This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05