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mestny [16]
2 years ago
13

Help me plsssssss !!!!

Mathematics
1 answer:
egoroff_w [7]2 years ago
7 0

Answer:

The answer to this would be  v, w, x (B)

Step-by-step explanation:

Three or more points that lie on the same line are collinear points

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9x+3y=18 whats is the equation when solved for y
lidiya [134]

Answer:

y=6-3x

Step-by-step explanation:

first subtract 9x from 9x+3y=18

                                   -9x       -9x

so you get 3y=18-9x or 3y=-9x+18 then divide both sides by 3

so you get y=6-3x hope this helps :)

6 0
3 years ago
Your family travels 336 miles in 6 hours.find the unit rate
mamaluj [8]

Answer:

122 po yan po dapat

Step-by-step explanation:

thanks me letter

8 0
2 years ago
Read 2 more answers
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
Rhianna invests $1200 in stock and bonds. The stock pays 9% interest and the bonds pay 6% interest. If the total ANNUAL interest
Strike441 [17]
0.06x+0.09 (1200-x)=96
Solve for x
X=400 at 6%

1200-400=800 at 9%
3 0
3 years ago
Read 2 more answers
Write f(x) = 2x2 – 44x 185 in vertex form. To write f(x) = 2x2 – 44x 185, factor out from the first two terms. Next, form a perf
Tasya [4]

The quadratic function f(x) = 2x² – 44x + 185 is written in vertex form is f(x) = 2(x –  11)² – 57.

<h3>What is a quadratic equation?</h3>

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

The quadrattic equation is f(x) = 2x² – 44x + 185.

Take common 2 from the equation, we have

f(x) = 2(x^2 - 22x )+ 185

Add and subtract 121, we have

f(x) = 2(x^2 - 22x +121 - 121 )+ 185\\\\f(x) = 2[(x^2 - 11)^2-121]+ 185\\\\f(x) = 2(x-11)^2 - 242 + 185\\\\f (x ) = 2(x-11)^2 -57

And we know that the standard equation

f(x) = a(x - h)² + k

On comparing, we have

The vertex (h, k) is (11, -57).

More about the quadratic equation link is given below.

brainly.com/question/2263981

5 0
2 years ago
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