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Elan Coil [88]
3 years ago
6

Graph the line y=−3x+b if it is known that the graph goes through point: B(5,2)

Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

Try this solution:

1. In order to built the line required in the condition it need to determine its equation.

Using the coordinates of point B (5;2), if to substitute them into the given equation: 2=-3*5+b, ⇒ b=17. It means, that the equation of the line required in the condition is y= -3x+17.

2. The graph is in the attachment; point (0;17) is the intersection point of Y-axis and the line.

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PLEASE HELP ME ASAP(WORTH 30 POINTS). If the domain is {0, 2, -6}, what is the range of y = -2x + 3?
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Domain = {0,2,-6}

function : y= -2x + 3

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Is f(x)=3x5^2x-3 an exponential function? If so, write it in the form f(x)=ab^x
Anna11 [10]

Answer:

f(x)=\frac{3}{125} * 25^x

Step-by-step explanation:

Given

f(x)=3*5^{2x-3}

Required

To determine if it is an exponential function, we have to write in form of

f(x) = ab^x

If we're able to do so, then the function is an exponential function.

If otherwise, then it is not

f(x)=3*5^{2x-3}

Apply Law of indices

f(x)=3*\frac{5^{2x}}{5^3}

Express 5^3 as 125

f(x)=3*\frac{5^{2x}}{125}

Factorize the exponent of 5

f(x)=3*\frac{5^{(2)x}}{125}

Express 5^2 as 25

f(x)=3*\frac{25^x}{125}

This can be rewritten as:

f(x)=\frac{3}{125} * 25^x

By comparing the above to f(x) = ab^x

We have that

a = \frac{3}{125}

b^x = 25^x

Since, we've be able to express the function as f(x) = ab^x

Then, f(x)=3*5^{2x-3} is an exponential function

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3 years ago
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