Answer:
rrtrrrfddddddddfffffffddddd
<span>Show my work
(8.86+1.0*10^3)/(3.610*10^-3)
</span>=<span><span>8.86+<span><span>(1)</span><span>(1000)/</span></span></span><span>3.61<span>(<span>10^<span>−3</span></span><span>)
</span></span></span></span><span>=<span><span><span>8.86+1000</span><span>3.61<span>(<span>10^<span>−3</span></span>)
</span></span></span>
</span></span>=<span>1008.86<span>3.61<span>(<span>10^<span>−3</span></span><span>)
</span></span></span></span>=<span>1008.86<span>3.61<span>(<span>1/1000</span><span>)
</span></span></span></span><span>
=<span><span>1008.86/0.00361
</span>
Answer is = </span></span><span>279462.603878
It will help you.</span>
Answer:
x= 5/2, x= -3
4x^2+2x-30=0; Factor that without the 0. Then you get 2 (2x-5) (x+3)=0.
2x-5=0 x= 5/2
x+3=0 x= -3
Hope this helps! :D
Answer:
2 what?
Step-by-step explanation:
Answer:
m ∠JPN = 131°
Step-by-step explanation:
m ∠JPL = m ∠MPK Vertical angles are =
7x + 19 = 11x -17 Substitution
- 4x = -36 Algebra: Solving for x
x = 9 Algebra: Solving for x
m ∠JPL = 82° Substitution x = 9 into m ∠JPL = 7x +19
m ∠JPL + m ∠LPK = 180° Definition of linear pair/supplement
angles = 180°
82° + m ∠LPK = 180° Substitution
m ∠LPK = 98° Algebra
m ∠LPK = m ∠LPN + m ∠NPK Angle addition Theorem
PN bisects ∠LPK Given
m ∠LPN = m ∠NPK Definition of angle bisector
98 ° = 2 ( m ∠LPN) Substitution
m ∠LPN = 49° Algebra
m ∠JPN = m ∠JPL + m ∠LPN Angle Addition
m ∠JPN = 82° + 49° Substitution
m ∠JPN = 131° Addition