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Elanso [62]
3 years ago
9

At joe’s restaurant, one fourth of the patrons are males and one fifth of the patrons are from out of town. What proportion woul

d you expect to be a male and out of town?
Mathematics
1 answer:
lana [24]3 years ago
8 0

Hey!

The probability of being a male is \frac{1}{4}. The probability of being from out of town is \frac{1}{5}.

Multiply both probabilities:

\frac{1}{4} \times \frac{1}{5} = \frac{1}{20}

<em>Your answer is</em> \frac{1}{20}

Good luck and hope this helps! :)

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hram777 [196]

Answer:

1.50

Step-by-step explanation:

8 0
3 years ago
Are the marks one receives in a course related to the amount of time spent studying the subject? To analyze this mysterious poss
sertanlavr [38]

Answer:

a) 98.522

b) 0.881

c) The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time.

Step-by-step explanation:

a.

As the mentioned in the given instruction the co-variance is first computed in excel by using only add/Sum, subtract, multiply, divide functions.

Marks y Time spent x y-ybar x-xbar (y-ybar)(x-xbar)

77                    40 5.1         1.3 6.63

63                     42 -8.9            3.3 -29.37

79                     37 7.1            -1.7 -12.07

86                     47 14.1            8.3 117.03

51                    25 -20.9  -13.7 286.33

78                     44 6.1            5.3 32.33

83                      41 11.1            2.3 25.53

90                     48 18.1            9.3 168.33

65                     35 -6.9           -3.7 25.53

47                    28 -24.9 -10.7 266.43

Covariance=\frac{sum[(y-ybar)(x-xbar)]}{n-1}

Co-variance=886.7/(10-1)

Co-variance=886.7/9

Co-variance=98.5222

The co-variance computed using excel function COVARIANCE.S(B1:B11,A1:A11) where B1:B11 contains Time x column and A1:A11 contains Marks y column. The resulted co-variance is 98.52222.

b)

The correlation coefficient is computed as

Correlation coefficient=r=\frac{sum[(y-ybar)(x-xbar)]}{\sqrt{sum[(x-xbar)]^2sum[(y-ybar)]^2} }

(y-ybar)^2 (x-xbar)^2

26.01        1.69

79.21       10.89

50.41             2.89

198.81       68.89

436.81       187.69

37.21       28.09

123.21        5.29

327.61        86.49

47.61         13.69

620.01         114.49

sum(y-ybar)^2=1946.9

sum(x-xbar)^2=520.1

Correlation coefficient=r=\frac{886.7}{\sqrt{520.1(1946.9)} }

Correlation coefficient=r=\frac{886.7}{\sqrt{1012582.69} }

Correlation coefficient=r=\frac{886.7}{1006.2717 }

Correlation coefficient=r=0.881

The correlation coefficient computed using excel function CORREL(A1:A11,B1:B11) where B1:B11 contains Time x column and A1:A11 contains Marks y column. The resulted correlation coefficient is 0.881.

c)

The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time. It means that as the study time increases the marks of student also increases and if the study time decreases the marks of student also decreases.

The excel file is attached on which all the related work is done.

Download xlsx
7 0
3 years ago
Please any help is necessary
Ugo [173]

Answer:

Option D. 50 ft

Step-by-step explanation:

we know that

The area of the figure is equal to the area of three rectangles

so

A=18x+(48-36)(32-11)+(18)(32)

A=18x+(12)(21)+(18)(32)\\A=18x+828

Remember that the area is given

A= 1,728\ ft^2

so

18x+828=1,728

solve for x

18x=1,728-828\\18x=900\\x=50\ ft

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3 years ago
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1. 11h

2. 10w

3. 6w

4.6 (h+3)

5. 74

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6 0
3 years ago
What is the 79th term of this arithmetic sequence? 3, 9, 15, 21,
hodyreva [135]
6 times 79 = 474 so the 79th term is 474
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3 years ago
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