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3 years ago

15

Hii please help i’ll give brainliest if you give a correct answer please please hurry it’s timed

1 answer:

Alexxandr [17]3 years ago

3 0

Answer:

The first book ur

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Can someone please help me with this logarithm equation!!

enot [183]

Answer:

$\frac{629}{2}$

Step-by-step explanation:

So, our equation is:

$log_5(\frac{2x-4}{5}) = 3$

In exponetial form, this looks like:

$5^3=\frac{2x-4}{5}$

Now lets cube the 5:

$125=\frac{2x-4}{5}$

Next, we can multiply the denominator on the right side by 5:

$625=2x-4$

We need to now get x alone by adding 4 to both sides:

$629=2x$

Finally, we divide by x's coefficent, 2, to get:

$x=\frac{629}{2}$

Hope this helps! :3

6 0

3 years ago

Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)

vekshin1

$\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}$

$\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )$

5 0

3 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

3 years ago

The radius of a circle is 4 feet. What is the circle's area? Use 3.14 for .

Serga [27]

Answer:

Approximately 50 square feet (50.24 to be exact)

Step-by-step explanation:

If you're using 3.14 for π, and the area of a circle is A=πr2,

(3.14)(4)^2 =?

(3.14)(16) = 50.24

Therefore the answer would be about 50 square feet.

3 0

3 years ago

Read 2 more answers

Divya starts a painting her grandpa's kitchen at 8:15 a.m. She finishes 75 minutes later

Mila [183]

Answer:

9:30 she finishes

Step-by-step explanation:

815 plus 75 is 890

there are 60 minutes in one hour

890-60 is 830

add 100 to represent another Hour

830 plus 100 is 930

9:30

therefore, it is 9:30

8 0

3 years ago