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3 years ago

Write three different integer addition expressions that equal −5.

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

4 0

Given:

Three different integer addition expressions equal −5.

To find:

The three different integer addition expressions.

Solution:

We know that 0 is the identity element under addition. It means if we add 0 to a number we get the same number.

$(-5)+0=-5$

One expression is $(-5)+0$ .

The other expression are:

$(-6)+1=-5$

$(-7)+2=-5$

Therefore, the three different integer addition expressions that are equal to -5 are $(-5)+0,(-6)+1,(-7)+2$ .

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Suppose the position of an object moving horizontally after t seconds is given by the following functions s=f(t), s equals f , o

Scilla [17]

Answer:

(a) The graph of position function is shown below.

(b) The velocity function is $v(t)=-2t+4$ and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(d) The acceleration of the object is -2 when its velocity is zero.

(e) The speed is not increasing at any interval because the acceleration is constant.

Step-by-step explanation:

(a)

The given function is

$f(t)=-t^2+4t-3; 0\leq t\leq 5$

The position of an object moving horizontally after t seconds is given by

$s=f(t)=-t^2+4t-3$

The graph of position function is shown below.

(b)

Differentiate the position function with respect to time to find the velocity function.

$v=f'(t)=-2t+4$

Put v=0 to find the time when the object is stationary.

$0=-2t+4$

$2t=4$

$t=2$

The object is stationary at t=2 because the velocity of the object is 0 at t=2.

The velocity function is $v(t)=-2t+4$ and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(c)

The velocity function is

$v=f'(t)=-2t+4$

Substitute t=1 in the above function.

$v=f'(1)=-2(1)+4=2$

Differentiate the velocity function with respect to time to find the acceleration function.

$a=f''(t)=-2$

Substitute t=1 in the above function.

$a=f''(1)=-2$

Therefore the velocity and acceleration of the object at t=1 are 2 and -2 respectively.

(d)

The velocity of the object is 0 at t=2.

Substitute t=2 in the acceleration function to find the acceleration of the object when its velocity is zero.

$a=f''(2)=-2$

The acceleration of the object is -2 when its velocity is zero.

(e)

The acceleration function of the object is

$a=f''(t)=-2$

It is a constant function.

Therefore the speed is not increasing at any interval because the acceleration is constant.

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3 years ago

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julia-pushkina [17]

Answer:

C) 50

Step-by-step explanation:

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Freya is training for a track race. She starts by sprinting 200 yards. She gradually increases her distance, adding 5 yards a da

KiRa [710]

Answer:

The explicit formula is:

$a_n = 200 +5(n-1)$

Step-by-step explanation:

Freya increases 5 yards daily to the number of yards she runs.

Note that the increase factor is constant, so this problem can be modeled using an arithmetic sequence.

The explicit formula for an arithmetic sequence is:

$a_n = n_1 + d(n-1)$

Where:

$a_n$ is the number of yards that Freya runs on the day

$a_1$ is the number of yards that he runs on day 1

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4 years ago

Which equation describes the same line as y-5 = -2(x + 4)?

natita [175]

Hi,

y - 5 = -2(x+4)

y - 5 = -2x - 8

y - 5 + 5 = -2x - 8 + 5

y = -2x -3

✅(•‿•)

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