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2 years ago

Write an equation of the line that passes through (-1,4) and is perpendicular to the line shown.

Mathematics

1 answer:

tatuchka [14]2 years ago

5 0

Answer:

Step-by-step explanation:

To write an equation that is perpendicular to a given line, take the negative reciprocal of the given slope. the given slope is 4/3, so the negative reciprocal is -3/4.

Using slope-intercept form of a linear equation, y=mx+b substitute in -3/4 for "m" the slope.

y=-3/4x+b

Now you need to "b" the y-intercept using the given point (-4,-1). Substitute the values in the equation. -1=-3/4(-4)+b simplify

-1= 3 + b subtract 3 for both sides

-4=b

substitue -4 for b. Now you have y= -3/4x - 4 this is your answer.

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What is the probability that a number selected at random from the set {2, 3, 7, 12, 15, 22, 72, 108} will be divisible by both 2

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$\frac{Total-numbers -divisible-by-2-and-3}{Total-numbers-in-set}$

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3 years ago

Solve 7x2(x + 1) = 6x + 14<br> Ox=-12<br> Ox = 12<br> Ox= -16<br> Ox = 16

Evgen [1.6K]

$\large\displaystyle\text{$\begin{gathered}\sf 7x-2(x+1)=6x+4 \end{gathered}$}$

Use the distributive property to multiply −2 by x+1.

$\large\displaystyle\text{$\begin{gathered}\sf 7x-2x-2=6x+14 \end{gathered}$}$

Combine 7x and −2x to get 5x.

$\large\displaystyle\text{$\begin{gathered}\sf 5x-2=6x+14 \end{gathered}$}$

Subtract 6x on both sides.

$\large\displaystyle\text{$\begin{gathered}\sf 5x-2-6x=14 \end{gathered}$}$

Combine 5x and −6x to get −x.

$\large\displaystyle\text{$\begin{gathered}\sf -x-2=14 \end{gathered}$}$

Add 2 to both sides.

$\large\displaystyle\text{$\begin{gathered}\sf -x=14+2 \end{gathered}$}$

Add 14 and 2 to get 16.

$\large\displaystyle\text{$\begin{gathered}\sf -x=16 \end{gathered}$}$

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$\large\displaystyle\text{$\begin{gathered}\sf x=-16 \ \ \to \ \ \ Answer \end{gathered}$}$

<h2>{ Pisces04 }</h2>

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1 year ago

Read 2 more answers

How do I find the all of the angle measures of a kite with only one given angle?

ohaa [14]

Use the geometery rules of a kite to fiugure it out

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3 years ago

What is the completely factored form of f(x)=x3+5x2+4x−6?

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$f(x)=x^3+5x^2+4x-6$
$f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)$

Synthetic division yields

-3 | 1   5   4   -6
.    |      -3 -6    6
- - - - - - - - - - - - -
.    | 1   2 -2    0

which translates to

$\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2$

with remainder 0. Now by the quadratic formula,

$x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3$

and so

$f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))$

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3 years ago

Determine the intercepts of the line.

Strike441 [17]

Answer:

Step-by-step explanation:

An intercept is where the line hits the axis.

Lets start with x. The x intercept is always going to be what x equals when y = 0. So we know the second value of the x intercept is going to be 0, because the second value is y. The line hits the x axis at -1.2, so the x intercept is -1.2, 0

The y intercept it what y equals when x equals 0. So the first value is going to be 0, to represent x. The line hits the y intercept at the point 0, -0.7.

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3 years ago