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yan [13]
3 years ago
12

If ABC is a right triangle with B the right angle, A=(-3,2) and B =(2,5), find possible

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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Find the value of x. x√5=x^4​
Kaylis [27]

Answer:

x=0,\sqrt[6]{5}

Decimal form,

x=0,1.30766048......

Step-by-step explanation:

x\sqrt{5}=x^{4}

x\sqrt{5}-x^{4}=0

(take x as a common factor)

x(\sqrt{5}-x^{3})=0

So,

x=0 and \sqrt{5}-x^{3}=0

for \sqrt{5-x^{3}=0

(add x^{3} for both sides)

\sqrt{5}=x^{3}

x=\sqrt[3]{\sqrt[2]{5} } (multiply 3 by 2)

x=\sqrt[6]{5}

So,

x=0,\sqrt[6]{5}

5 0
3 years ago
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3*p using p to represent the peaches Ethan picked
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3 years ago
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Naddik [55]

Answer:

4 inches

Step-by-step explanation:

The line that is perpendicular to the bottom of the trapezoid is the height.

5 0
3 years ago
PLEASE ANSWER!!!!!! WILL MARK BRAINLIEST!!!!!!
docker41 [41]

Answer:

sinB= 3/5, tanA=4/3, cosB=4/5

Step-by-step explanation:

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PRECALC QUESTION! Convert the polar representation of this complex number into its standard form: z = 2(cos 11pi/6+ i sin 11pi/6
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\bf z=2\left[ cos\left( \frac{11\pi }{6} \right) + i\ sin\left( \frac{11\pi }{6} \right) \right]\qquad 
\begin{cases}
r=2\\
\theta=\frac{11\pi }{6}\\
-----\\
a=x=rcos(\theta)\\
b=y=rsin(\theta)
\end{cases}\implies a+bi
\\\\\\
2cos\left( \frac{11\pi }{6} \right)+2sin\left( \frac{11\pi }{6} \right)\ i\implies 2\cdot \cfrac{\sqrt{3}}{2}+2\cdot \cfrac{-1}{2}\ i\implies \sqrt{3}-1i
\\\\\\
\boxed{\sqrt{3}-i}
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3 years ago
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