Answer:
F = 0i (in the x-direction), 0j (in the y-direction),-8.59*10^-4 N k (In the z-direction)
Explanation:
The force given by charged particles moving in a magnetic field is given below (cross is cross product, they don't have that format in the equation tool):

Now we can perform the cross product between v and B
d{array}\right][/tex]
Now multiply by Q (charge) to get the force

F = -8.59*10^-4 N k
F = 0i, 0j, (-8.59*10^-4)k
Answer:
966.22 mph
Explanation:
Velocity of plane with respect to wind (Vp,w)= 612 mph east
velocity of wind with respect to ground, (Vw,g) = 362 mph at 15° North of
east
Write the velocities in vector form


Use the formula for the relative velocity

Where, V(p,w) is the velocity of plane with respect to wind
V(p,g) is the velocity of plane with respect to ground
V(w,g) is the velocity of wind with respect to ground
So, 


Magnitude of velocity of lane with respect to ground

V(p,g) = 966.22 mph
Producing a current by moving a wire through a magnetic field is called ELECTROMAGNETIC INDUCTION.
Electromagnetic induction refers to the production of an electromotive force across an electrical conductor in a changing magnetic field. The process was discovered by Micheal Faraday in 1831.
Incomplete question.The complete one is here
A runner taking part in the 200m dash must run around the end of a track that has a circular arc with a radius curvature of 30m. The runner starts the race at a constant speed. If she completes the 200m dash in 23s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track?
Answer:

Explanation:
Given data

Required
Centripetal acceleration
Solution
According to the motions equation the velocity given by:

The centripetal acceleration is given by:
