The particle’s force is <em><u>( - 8.59 × 10⁻⁴ </u></em><em><u>k</u></em><em><u> ) N</u></em>
<h3>Further explanation</h3>
<em>Let's recall </em><em>magnetic force on moving charge</em><em> as follows:</em>
<em>where:</em>
<em>F = magnetic force ( N )</em>
<em>B = magnetic field strength ( T )</em>
<em>q = charge of object ( C )</em>
<em>v = speed of object ( m/s )</em>
<em>θ = angle between velocity and direction of the magnetic field </em>
Let's tackle the problem now !
<u>Given:</u>
speed of particle = v_y = -3.85 × 10⁴ m/s
magnetic field strength = B_x = 1.80 T
charge of particle = q = -1.24 × 10⁻⁸ C
direction of speed = θ = 90°
<u>Asked:</u>
the particle's force = F = ?
<u>Solution:</u>
<em>According to the Left Hand Rule , the direction of force is in </em><em>negative z-axis.</em>
We could write this force in vector form as follows:
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Magnetic Field