Answer:
Lifetime = 4.928 x 10^-32 s
Explanation:
(1 / v2 – 1 / c2) x2 = T2
T2 = (1/ 297900000 – 1 / 90000000000000000) 0.0000013225
T2 = (3.357 x 10^-9 x 1.11 x 10^-17) 1.3225 x 10^-6
T2 = (3.726 x 10^-26) 1.3225 x 10^-6 = 4.928 x 10^-32 s
2: Fusion occurs constantly on our sun.When nuclei fuse create a heavier nuclear and produce a little leftover energy in the process
Answer:
6.0cm
Explanation:
Given
focal length = 15.0cm
object distance = 10.0cm
Required
Image distance v
Using the formula
1/f = 1/u + 1/v
1/15 = 1/10+1/v
1/v = 1/15 + 1/10
1/v = 2+3/30
1/v = 5/30
v = 30/5
v = 6.0cm
Hence the image distance is 6.0cm
Answer:
d. 87,500 J
e. 49,600 J
Explanation:
The total energy is the heat absorbed by the copper plus the heat absorbed by the water.
d)
E = m₁C₁ΔT + m₂C₂ΔT
E = (1 kg) (390 J/kg/°C) (10 °C) + (2 kg) (4180 J/kg/°C) (10 °C)
E = 87,500 J
e)
E = m₁C₁ΔT + m₂C₂ΔT
E = (2 kg) (390 J/kg/°C) (10 °C) + (1 kg) (4180 J/kg/°C) (10 °C)
E = 49,600 J
