The answer is either C or D..
Answer:
Available energy = 35 x 10⁶ J
Explanation:
Given:
Amount of energy (Q) = 21 gj = 21 x 10⁹ J
Temperature T1 = 600 k
Temperature T0 = 27 + 273 = 300k
Find:
Available energy
Computation:
Available energy = Q[1/T0 - 1/T1]
Available energy = 21 x 10⁹ J[1/300 - 1/600]
Available energy = 35 x 10⁶ J
Answer:
which of the cars are speeding up: c
which of the cars or slowing down: a
which of the cars are maintaning a constant speed: b
Explanation:
Answer:
KE = 2.03 J
Explanation:
After impact, the kinetic energy of the bullet+block will convert to potential energy
½mv² = mgh
v = √(2gh) = √(2(9.81)(0.00500) = 0.0981 m/s
conservation of momentum during the collision
0.015u + 2.50(0) = (2.50 + 0.015)(0.0981)
u = 16.4481 m/s
KE = ½mv² = ½(0.015)16.4481² = 2.0290499...
KE = 2.03 J
Answer:
option A
Explanation:
given,
Kinetic energy of the car = 2000 J
speed of the car is doubled
we know,
........(1)
now, speed of the car is doubled
v' = 2 v
from equation (1)
Hence, the Kinetic energy would be equal to 8000 J.
The correct answer is option A.
